SELECT * FROM events e LEFT JOIN venue v ON v.id=e.venueid
CROSS JOIN (select (((5*sum(rating = 5))+(4*sum(rating = 4))+(3*sum(rating = 3))+(2*sum(rating = 2))+sum(rating = 1))/count(*)) rating
from feedbacks where boxid = **e.boxid**) r
WHERE e.startdate = CURDATE() AND e.starttime >= CURTIME()
LIMIT 10;
我无法访问子查询中的 e.boxid 。有人可以帮忙吗?
答案 0 :(得分:2)
另一种方法是使用相关子查询:
SELECT e.*, v.*,
(SELECT (((5*sum(rating = 5))+(4*sum(rating = 4))+(3*sum(rating = 3))+(2*sum(rating = 2))+sum(rating = 1))/count(*)) as rating
FROM feedbacks f
WHERE f.boxid = e.boxid
) as rating
FROM events e LEFT JOIN
venue v
ON v.id = e.venueid
WHERE e.startdate = CURDATE() AND e.starttime >= CURTIME()
LIMIT 10;
在这种情况下,因为WHERE
子句过滤掉了许多记录(可能),相关子查询可能比GROUP BY
更有效。如果您在feedbacks(boxid)
中有索引,则尤其如此。
答案 1 :(得分:1)
使用GROUP BY
上的boxid
将其带到子查询之外,然后将其与events
列上的boxid
表一起加入,如下所示:
SELECT
*
FROM
events e
LEFT JOIN
venue v ON v.id = e.venueid
JOIN
(SELECT
boxid,
(((5 * SUM(rating = 5)) + (4 * SUM(rating = 4)) + (3 * SUM(rating = 3)) + (2 * SUM(rating = 2)) + SUM(rating = 1)) / COUNT(*)) rating
FROM
feedbacks
GROUP BY boxid) r ON e.boxid = r.boxid
WHERE
e.startdate = CURDATE()
AND e.starttime >= CURTIME()
LIMIT 10;
您还可以使用相关的子查询:
SELECT e.*,
v.*,
(SELECT (((5*SUM(rating = 5))+(4*SUM(rating = 4))+(3*SUM(rating = 3))+(2*SUM(rating = 2))+SUM(rating = 1))/COUNT(*)) AS rating
FROM feedbacks f
WHERE f.boxid = e.boxid
) rating
FROM events e
LEFT JOIN venue v
ON v.id = e.venueid
WHERE e.startdate = CURDATE()
AND e.starttime >= CURTIME() LIMIT 10;