试图解密加密的十六进制代码，找到密钥，然后转换为英文

Question

目标：解码加密的十六进制，这需要查找未知的单字符密钥

我纯粹是试图通过对每个ascii字符的xOR中的每个字符进行异或来解决问题。我期待得到一个字符串作为我的输出之一。但是，我的catch语句说它返回的每个字符串都不是十六进制。

然后，我计划将这些转换后的十六进制值转换为chars。 如果你能为我提供一些如何解决这个暴行的指导，那将会非常有用。

非常感谢！

//intention of this program is to decrypt this string of encoded hex, find the key, and decrpt the message
//however, its not really working. It doesnt print values prior to 112 even though those values arent blank
// as I checked in debugger

public static void main(String[] args) throws UnsupportedEncodingException
{
    String xOr1 = ("1b37373331363f78151b7f2b783431333d78397828372d363c78373e783a393b3736");
    String xOr = "z({zzz{{z-{z{z{{{}z*{y)~x~x~{{rzsz(";
    String result = "";

    System.out.println("xOr1 length is " + xOr1.length());
    String output = "";

    byte[] encoded = xOr1.getBytes();
    byte[] decoded;
    String sub;

    String matches = "(.*)abdef0123456789(.*)";
    int hexInt;
    for(int k = 0; k< 256;k++)
    {
        decoded = new byte[encoded.length];
        result = "";
        System.out.println(k);
        for(int j = 0; j<encoded.length; j++)
        {
            decoded[j] = (byte)((int)encoded[j] ^ k);
            result = Arrays.toString(decoded);

        }
        output = new String(decoded,"UTF-8");
        //System.out.println(output);

        try
        {
            for(int i = 0; i< output.length() -2; i++)
            {

                hexInt = Integer.parseInt(output,16);
                System.out.println("You aren't dumb... " + output);
            }
        }
        catch(NumberFormatException nfe)
        {
            //System.out.println(output);
            System.out.println("bad boy");
        }



    }


}