Question

这是我的电子邮件表单代码。它工作得非常好 - 将所有内容发送到我的地址电子邮件。有一个问题和我的问题。我是如何做到的我可以回复从表格收到的电子邮件？我的意思是，用户在电子邮箱中键入他的电子邮件地址，所以我想简单回复它，所以发件人应该是作者的电子邮件。现在它是myname@mydomain-where-i-have-my-website.com。它应该采取这种形式＆＃39;电子邮件＆＃39;。我是一个很棒的php noobie。

HTML代码

<h2>Contact form</h2>
                        <div id="send_form_status"></div>
                            <form method="post" action="/kontakt.php" id="contact_form">

                                <div><label for="name">Subject</label></div>
                                <div><input type="text" name="name" id="name"  required> </div>

                                <div><label for="email">E-mail</label></div>
                                <div><input type="email" name="email"  required></div>

                                <div><label for="message">Message</label></div>
                                <div><textarea name="message" id="message"  required></textarea></div>

                                <div><input type="submit" id="submint" name="submint" value="Send"></div>

                            </form>

PHP代码

<?php
header("content-type: application/json; charset=utf-8");

$name = $_POST['name'];
$email = $_POST['email'];
$message = $_POST['message'];

$to = "myname@something.pl";
$subject = "Welcome";

if($name && $email && $message){
 $headers = "MIME-Version: 1.0\r\nContent-type: text/plain; charset=utf-8\r\nContent-Transfer-Encoding: 8bit";

 $message_body = "";
 $message_body .= "Subject: " . $name . "\n";
 $message_body .= "From: " . $email . "\n";
 $message_body .= "Message: \n" . $message . "\n";

 if(mail($to,$subject,$message_body,$headers)){
 $json=array("status"=>1,"msg"=>"<p class='status_ok'>Message send.</p>");
 }
 else{
 $json=array("status"=>0,"msg"=>"<p class='status_err'>Faild to send.</p>"); 
 }
}
else{
 $json=array("status"=>0,"msg"=>"<p class='status_err'>The all fields are required.</p>"); 
}
echo json_encode($json);
exit;
?>

已更新
正如我在评论中写的那样。要解决此问题，我删除了所有 $ message_body ：

 $message_body = "";
 $message_body .= "Subject: " . $name . "\n";
 $message_body .= "From: " . $email . "\n";
 $message_body .= "Message: \n" . $message . "\n";

添加邮件标题和表单内容：

  $mailheader = "MIME-Version: 1.0\r\n";
  $mailheader = "Content-type: text/plain; charset=utf-8\r\n";
  $mailheader = "From: ".$email." \n\r";
  $formcontent="Subject: $name \n Message: \n $message \n" ;

并改变了这个：

if(mail($to,$subject,$message_body,$headers))

对此：

if(mail($to,$subject,$formcontent,$mailheader))

回复发件人adres电子邮件PHP

0 个答案: