我正在使用UISearchBar(但不是通常联合使用的SearchDisplayController),我想在点击“X”按钮时关闭键盘。
当点击'X'并且效果很好时,我跟着TomSwift's suggestion被叫了。但是,从文本字段中退出第一个响应者并在UISearchBar实例中调用resignFirstResponder
,都不会使键盘消失。
当用户轻敲X按钮时,有没有办法摆脱键盘?
以下是我通过“清除”通知所做的工作:
- (void)viewDidLoad:
{
for (UIView* v in searchBar.subviews)
{
if ( [v isKindOfClass: [UITextField class]] )
{
UITextField *tf = (UITextField *)v;
tf.delegate = self;
break;
}
}
}
然后我有我的类设置来实现UISearchBarDelegate和UITextFieldDelegate。
将课程作为文本字段委托,我可以接听此电话:
- (BOOL)textFieldShouldClear:(UITextField *)textField
{
[textField resignFirstResponder];
[self.searchBar resignFirstResponder];
return YES;
}
我已经尝试了我能想到的一切。我正在尝试的最后一件事是找到一种方法来发出UISearchDelegate将在我的Controller类上调用的'searchBarCancelButtonClicked',但不是我确定我怎么能这样做,因为UISearchBar似乎没有任何直接的方法用这个名字调用。
答案 0 :(得分:71)
- (void)searchBar:(UISearchBar *)searchBar textDidChange:(NSString *)searchText
{
[self performFilteringBySearchText: searchText]; // or whatever
// The user clicked the [X] button or otherwise cleared the text.
if([searchText length] == 0) {
[searchBar performSelector: @selector(resignFirstResponder)
withObject: nil
afterDelay: 0.1];
}
}
像汤姆的恕我直言,像魅力一样,不那么狡猾。
答案 1 :(得分:6)
这有效:
[searchBar performSelector:@selector(resignFirstResponder) withObject:nil afterDelay:0.1];
答案 2 :(得分:3)
Swift 2版本:
func searchBar(searchBar: UISearchBar, textDidChange searchText: String) {
// The user clicked the [X] button or otherwise cleared the text.
if (searchText.characters.count == 0) {
searchBar.performSelector("resignFirstResponder", withObject: nil, afterDelay: 0.1)
}
}
答案 3 :(得分:3)
更新了SWIFT 3:
假设用户在搜索字段中输入了一个字符串并单击了x,以下代码可以在按下x时隐藏键盘
`
func searchBar(_ searchBar: UISearchBar, textDidChange searchText: String)
{
if searchBar.text == nil || searchBar.text == ""
{
searchBar.perform(#selector(self.resignFirstResponder), with: nil, afterDelay: 0.1)
}
}
`
答案 4 :(得分:2)
- (void)searchBarTextDidEndEditing:(UISearchBar *)searchBar
{
SearchBar.showsCancelButton =NO;
}
- (void)searchBarCancelButtonClicked:(UISearchBar *)searchBar
{
[SearchBar resignFirstResponder];
}
答案 5 :(得分:2)
<强>更新强>
嗯,这完全是黑客,但我能够让它发挥作用。基本上,代码调用取消按钮的处理程序。为了使它工作,我不得不延迟调用选择器,我不知道为什么这是必须的。另外,我必须为取消按钮编写一个访问器,就像你为文本字段所做的那样。
同样,这是一次彻底的黑客行为。我不确定自己是否会在应用程序中自己这样做。
// this in the context of the search bar
- (UIButton*) cancelButton
{
for (UIView* v in self.subviews)
{
if ( [v isKindOfClass: [UIButton class]] )
return (UIButton*)v;
}
return nil;
}
// this is the textField delegate callback
- (BOOL)textFieldShouldClear:(UITextField *)textField
{
[textField resignFirstResponder];
UIButton* cb = _searchBar.cancelButton;
NSObject* target = [[cb allTargets] anyObject];
NSArray* actions = [cb actionsForTarget: target forControlEvent:UIControlEventTouchUpInside];
NSString* selectorName = [actions objectAtIndex:0];
SEL selector = NSSelectorFromString( selectorName );
[target performSelector: selector withObject: cb afterDelay: 0.1];
return YES;
}
原始回答:
如何在第一时间显示清晰的“X”按钮?在我的测试用例中,我没有看到它显示...
尝试在searchBar上执行resignFirstResponder,而不是textField。
答案 6 :(得分:1)
答案 7 :(得分:1)
尽量避免
- (BOOL)searchBarShouldEndEditing:(UISearchBar *)searchBar
代码中的方法我们可以解决这个问题
答案 8 :(得分:1)
我使用@ radiospiel的答案以及@Tozar linked给出的答案:
@interface SearchViewController : UIViewController <UISearchBarDelegate> {
// all of our ivar declarations go here...
BOOL shouldBeginEditing;
....
}
...
@end
@implementation SearchViewController
...
- (id)initWithNibName:(NSString *)nibNameOrNil bundle:(NSBundle *)nibBundleOrNil {
if ((self = [super initWithNibName:nibNameOrNil bundle:nibBundleOrNil])) {
...
shouldBeginEditing = YES;
}
}
...
- (void) searchBar:(UISearchBar *)theSearchBar textDidChange:(NSString *)searchText {
// TODO - dynamically update the search results here, if we choose to do that.
if (![searchBar isFirstResponder]) {
// The user clicked the [X] button while the keyboard was hidden
shouldBeginEditing = NO;
}
else if ([searchText length] == 0) {
// The user clicked the [X] button or otherwise cleared the text.
[theSearchBar performSelector: @selector(resignFirstResponder)
withObject: nil
afterDelay: 0.1];
}
}
- (BOOL)searchBarShouldBeginEditing:(UISearchBar *)bar {
// reset the shouldBeginEditing BOOL ivar to YES, but first take its value and use it to return it from the method call
BOOL boolToReturn = shouldBeginEditing;
shouldBeginEditing = YES;
return boolToReturn;
}
@end
答案 9 :(得分:1)
不应在主线程上进行UI更改而不是使用performselector:WithObject:afterDelay:
?
- (void)searchBar:(UISearchBar *)searchBar textDidChange:(NSString *)searchText
{
if (searchText.length == 0) {
[searchBar performSelectorOnMainThread:@selector(resignFirstResponder) withObject:nil waitUntilDone:NO];
}
}
答案 10 :(得分:0)
编辑:实际上,下面会破坏连接到UISearchBar的委托。只需子类化UISearchBar并覆盖UITextField Delegate方法。
===========================
我必须这样才能访问UITextView
for (UIButton* v in [self.searchBar.subviews[0] subviews])
{
if ( [v isKindOfClass: [UITextField class]] )
{
UITextField *tf = (UITextField *)v;
tf.delegate = self;
break;
}
}
答案 11 :(得分:0)
感谢Maxhs的原始回答: 这是swift 2.2版本: 像我一样的魅力
if searchBar.text == "" {
dispatch_async(dispatch_get_main_queue(), {
self.searchBar.resignFirstResponder()
})
}
答案 12 :(得分:0)
清晰文本流的另一种观点(类似于@TomSwift的回答,但对我来说更清晰,更不用说)。此外,我需要在退出搜索栏后隐藏取消按钮,在用户完成搜索之前实施实时搜索(在每个符号之后)和覆盖表。
//self.searchHoverView can cover table view
//performSearchWithSearchBar: method for performing search
#pragma mark - UISearchBarDelegate
- (void)searchBarTextDidBeginEditing:(UISearchBar *)searchBar {
[searchBar setShowsCancelButton:YES animated:YES];
self.searchHoverView.hidden = NO;
}
- (void)searchBar:(UISearchBar *)searchBar textDidChange:(NSString *)searchText {
if (searchText.length) {
[self performSearchWithSearchBar:searchBar];
} else {
UIButton *button;
for (UIView *subView in [searchBar subviews]) {
for (UIView *view in [subView subviews]) {
if ([view isKindOfClass:[UIButton class]]) {
button = (UIButton *)view;
break;
}
}
}
if (button) {
dispatch_after(dispatch_time(DISPATCH_TIME_NOW, (int64_t)(0.1 * NSEC_PER_SEC)), dispatch_get_main_queue(), ^{
[button sendActionsForControlEvents:UIControlEventTouchUpInside];
});
}
}
}
- (void)searchBarCancelButtonClicked:(UISearchBar *)searchBar {
self.searchBar.text = nil;
[self.searchBar setShowsCancelButton:NO animated:YES];
[self.searchBar resignFirstResponder];
self.searchHoverView.hidden = YES;
}
答案 13 :(得分:0)
单击“ x”按钮时,搜索栏文本字段中的字符串将成为一个空字符集合。
检查集合的长度有助于检测何时单击了“ x”按钮。
我遇到了类似的问题,该解决方案对我有用:
func searchBar(_ searchBar: UISearchBar, textDidChange searchText: String) {
//let searchText = searchText.trimmingCharacters(in: .whitespaces)
if searchText.isEmpty{
DispatchQueue.main.async { [weak self] in
guard let self = self else{ return }
self.searchBar.resignFirstResponder()
}
}
}