Question

问题是没有回发。我注意到，如果我返回真的，那就不是这样了。但是有非确定性结果，所以我不知所措。任何帮助表示赞赏！

          <DropDownList ID="ddlS1" runat="server" onclick = "checkHighDegreeCompliance(this, 1);" SelectedIndexChanged = "ddlS1_SelectedIndexChanged" AutoPostBack="true" >

这是加载后实际页面上的标记

<select name="rptrSection1$ctl00$rptrSection2$ctl00$ddlS2" class="DDLSelector2 SDropDown IsNormal" id="rptrSection1_ctl00_rptrSection2_ctl00_ddlS2" style="width: 200px;" onchange="checkHighDegreeCompliance(this, 2);setTimeout('__doPostBack(\'rptrSection1$ctl00$rptrSection2$ctl00$ddlS2\',\'\')', 0)">

这是javascript

function checkHighDegreeCompliance(obj, sectionNum)
{
var parDdl = $(obj);
var parCompLev = parDdl.attr('selectedIndex');
var pnlDiv = parDdl.parents('.Section');
var ddls = pnlDiv.find('.DDLSelector' + (sectionNum + 1));
ddls.each(function ()
{
    var childDDL = $(this);
    var childComLev = childDDL.attr('selectedIndex');
    if (childComLev > parCompLev)
    {
        parDdl.attr('selectedIndex', childComLev);
    }
    if (sectionNum < 4)
    {
        checkHighDegreeCompliance(childDDL, ++sectionNum);
    }
});
}

Answer 1

在return事件

之前使用onclick关键字进行尝试

 <DropDownList ID="ddlS1" runat="server" onclick = "return checkHighDegreeCompliance(this, 1);" SelectedIndexChanged = "ddlS1_SelectedIndexChanged" AutoPostBack="true" >

如果不起作用，请告诉我。

将我的jquery与onclick事件混合，该事件也与SelectedIndexChanged事件相关联

1 个答案: