我无法解决以下问题:
<html>
<head>
<title>Test</title>
<script>
function myFunction(arr) {
var N = [0,1,2,3,4,5,6,7,8,9];
for (var s in N) {
var pattern = new RegExp('/^[A-z]et_[' + s + ']_\\d/');
// NOTE I get the following, is that how it should be?
// window.alert(pattern); => /\/^[A-z]et_[0]_\d\//
// NOTE: I checked that it works fine for a single digit case, say:
// var pattern = new RegExp(/^[A-z]et_[3]_\d/);
var newarr = arr.filter(elt => pattern.test(elt));
document.getElementById("demo").innerHTML = newarr;
}}
</script>
</head>
<body>
<div id="demo" onclick="myFunction(['aaaLet_0_0', 'Let_1_99', 'Let_2_', 'Let_3_99', 'Pet_2_', 'Pet_3_99', '_9_33']);">click here</div>
<hr>
<p>expected output: Let_1_99, Let_3_99, Pet_3_99</p>
</body>
</html>
我看到很多类似的问题,但我无法找到如何修复我的代码。它应该是可能的,不应该吗?
EDIT 以下是我的需要:
<html>
<head>
<title>Test</title>
<script>
var newarr = [];
function myFunction(arr) {
var N = [0,1,2,3,4,5,6,7,8,9];
for (var s in N) {
var pattern = new RegExp('^[A-z]et_' + s + '_\\d'); // NOTE: not /
var lnewarr = arr.filter(elt => pattern.test(elt));
if(typeof lnewarr !== 'undefined' && lnewarr.length > 0){newarr.push(lnewarr)};
}
document.getElementById("demo").innerHTML = newarr;
}
</script>
</head>
<body>
<div id="demo" onclick="myFunction(['aaaLet_0_0', 'Let_1_99', 'Let_2_', 'Let_3_99', 'Pet_2_', 'Pet_3_99', '_9_33']);">click here</div>
<hr>
<p>expected output: Let_1_99, Let_3_99, Pet_3_99</p>
</body>
</html>
(对不起,如果我的帖子主要是代码。希望它可以帮助那里的人。)
答案 0 :(得分:1)
您可以使用for
代替.join
循环代替{<1}}:
var pattern = new RegExp('^[A-Za-z]et_[' + N.join('') + ']_\\d');
//=> /^[A-Za-z]et_[0123456789]_\d/
这适用于数组N
中有单个字符值的情况。
对于通用用法,您可以使用以下表达式:
var pattern = new RegExp('^[A-Za-z]et_(?:' + N.join('|') + ')_\\d');
//=> /^[A-Za-z]et_(?:0|1|2|3|4|5|6|7|8|9)_\d/
使用for循环可以执行此操作:
var N = [0,1,2,3,4,5,6,7,8,9];
var str='(?:';
for (var s in N)
str += s + '|';
str = str.replace(/\|$/, ')');
var pattern = new RegExp('^[A-Za-z]et_' + str + '_\\d');
//=> /^[A-Za-z]et_(?:0|1|2|3|4|5|6|7|8|9)_\d/