Question

例如，如果我有代码：

for row in self.reader:
    if row:
        if row[0] == "Stage * Disk Face":
            """CODE TO EXECUTE"""

但是，有没有办法让星号*任意数字，以便在找到字符串"Stage 1 Disk Face"或"Stage 2 Disk Face"或"Stage 3 Disk Face"等时，代码会执行吗？原因并不是每个阶段编号都有磁盘面功能。我基本上需要找出是否至少有一个，任意数字。

Answer 1

这应该有效：

import re

for row in self.reader:
    if row:
        if re.match('^Stage [0-9]+ Disk Face$', row[0]):
            """CODE TO EXECUTE"""

Answer 2

检查

# coding=utf8
# the above tag defines encoding for this document and is for Python 2.x compatibility

import re

regex = r"(Stage )[0-9]( Disk Face)"

test_str = "Stage 1 Disk Face"

matches = re.search(regex, test_str)

if matches:
    print ("Match was found at {start}-{end}: {match}".format(start = matches.start(), end = matches.end(), match = matches.group()))

    for groupNum in range(0, len(matches.groups())):
        groupNum = groupNum + 1

        print ("Group {groupNum} found at {start}-{end}: {group}".format(groupNum = groupNum, start = matches.start(groupNum), end = matches.end(groupNum), group = matches.group(groupNum)))

# Note: for Python 2.7 compatibility, use ur"" to prefix the regex and u"" to prefix the test string and substitutio

Answer 3

//replace with the below code
$config['uri_protocol'] = "REQUEST_URI"

Answer 4

使用正则表达式最简单：

import re

rows = [["Stage 1 Disk Face"], ["Stage 2 Disk Face"], ["Stage 3 Disk Face"]]
pattern = re.compile("Stage .* Disk Face")

for row in rows:
    if row:
        if pattern.match(row[0]):
            print(row[0])

什么是将通配符整数放入字符串的最简单方法？

4 个答案: