private void getUsersWithin24Hours(String id, Map < String, Object > payload) throws JSONException {
JSONObject json = new JSONObject(String.valueOf(payload.get("data")));
Query query = new Query();
query.addCriteria(Criteria.where("user_id").is(id).and("timezone").in(json.get("timezone")).and("gender").in(json.get("gender")).and("locale").in(json.get("language")).and("time").gt(getDate()));
mongoTemplate.getCollection("user_log").distinct("user_id", query.getQueryObject());
}
我打算查询并从mongodb获得结果,我用mongo终端命令成功了:
db.getCollection('user_log').find({"user_id" : "1", "timezone" : {$in: [5,6]}, "gender" : {$in : ["male", "female"]}, "locale" : {$in : ["en_US"]}, "time" : {$gt : new ISODate("2017-01-26T16:57:52.354Z")}})
但是当我尝试时从java中给出了以下错误。
org.bson.codecs.configuration.CodecConfigurationException:无法找到 类org.json.JSONArray的编解码器
这样做的理想方法是什么?
提示:实际上我认为我的代码错误发生在这部分json.get(&#34; timezone&#34;)。因为它包含数组。当我使用硬编码字符串数组时,此代码可以正常工作
答案 0 :(得分:1)
以下是来自MongoDB University course的MongoDB示例,其中MongoDB数据库名为&#34;学生&#34;一个名为&#34; grade&#34; :
<强>的pom.xml 强>
<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd">
<modelVersion>4.0.0</modelVersion>
<groupId>com.mongodb</groupId>
<artifactId>test</artifactId>
<version>1.0-SNAPSHOT</version>
<packaging>jar</packaging>
<name>test</name>
<url>http://maven.apache.org</url>
<properties>
<project.build.sourceEncoding>UTF-8</project.build.sourceEncoding>
</properties>
<dependencies>
<dependency>
<groupId>org.mongodb</groupId>
<artifactId>mongodb-driver</artifactId>
<version>3.2.2</version>
</dependency>
</dependencies>
</project>
<强> COM /蒙戈/ Main.java 强>
package com.mongo;
import com.mongodb.MongoClient;
import com.mongodb.client.*;
import org.bson.Document;
import org.bson.conversions.Bson;
import javax.print.Doc;
public class Main {
public static void main(String[] args) {
MongoClient client = new MongoClient();
MongoDatabase database = client.getDatabase("students");
final MongoCollection<Document> collection = database.getCollection("grades");
Bson sort = new Document("student_id", 1).append("score", 1);
MongoCursor<Document> cursor = collection.find().sort(sort).iterator();
try {
Integer student_id = -1;
while (cursor.hasNext()) {
Document document = cursor.next();
// Doing more stuff
}
} finally {
cursor.close();
}
}
}
答案 1 :(得分:1)
您不必使用JSONObject/JSONArray
进行转换。
如果payload.get("data")
为Map
BasicDBObject json = new BasicDBObject(payload.get("data"));
如果payload.get("data")
包含json字符串,则替换为以下行。
BasicDBObject json =(BasicDBObject) JSON.parse(payload.get("data"));