MySQL phpMyAdmin从外键

Question

我正在使用LAMP并通过phpMyAdmin维护MySQl。每次我想在InnoDB表上构建一个多表查询时，我都厌倦了键入JOIN。

有没有人知道从外键生成JOIN语句的某些功能，插件，方法或资源？

Answer 1

我最终编写了一个从所有外键构建JOIN语句的查询：

CREATE VIEW Joins_All AS 
SELECT 
    concat(" JOIN ",TABLE_NAME," ON ",
    TABLE_NAME,".",COLUMN_NAME," = ",
    REFERENCED_TABLE_NAME,".", REFERENCED_COLUMN_NAME) 
    AS myJoin 
  FROM INFORMATION_SCHEMA.KEY_COLUMN_USAGE
  WHERE REFERENCED_TABLE_NAME IS NOT NULL 

UNION

SELECT  
    concat(" JOIN ",REFERENCED_TABLE_NAME," ON ",
    TABLE_NAME,".",COLUMN_NAME," = ",
    REFERENCED_TABLE_NAME,".", REFERENCED_COLUMN_NAME) 
    AS myJoin 
  FROM INFORMATION_SCHEMA.KEY_COLUMN_USAGE
  WHERE REFERENCED_TABLE_NAME IS NOT NULL 

ORDER BY myJoin  ASC

它生成这样的东西：

  

JOIN区域ON Area_Tare.Id_Area = Area.Id_Area

     

JOIN Area_Tare ON Area_Tare.Id_Area = Area.Id_Area

     

加入Insect ON Insect.Id_Insect_Class = Insect_Class.Id_Insect_Class

     

加入Insect on Insect_Insumo_Formula_Ingredient.Id_Insect = Insect.Id_Insect

我保存了这个文件并复制/粘贴了相应的行，我需要它们或者我使用所需表格的名称过滤视图

这可以很容易地在php中进行调整（我现在不会这样做）以创建基于外键的GUI查询构建器。任何决定这样做的人，请随意使用/改编此代码。