Question

我需要的是测试每个日期分组的每一行，并计算其中找到的某个模式的计数。在这个例子中查找并计算＆＃34; D;＆＃34;每个日期

样品

My expected output to be displayed into textbox

01 - 3

02 - 0

3 - 4

现在，我已经开始只是读取文本文件显示文本文件中的行数。

 protected void btnRead_Click(object sender, EventArgs e)
    {
        string text = String.Empty;
        int i = 0;
        using (StreamReader stRead = new StreamReader(FileUpload1.PostedFile.InputStream))
        {

            //to write textfile content         
            while (!stRead.EndOfStream)
            {
                //ListBox1.Items.Add(stRead.ReadLine());

                text += stRead.ReadLine() + Environment.NewLine;


                i++;
            }
        }

        TextBox1.Text = text;
        //Label1.Text = i.ToString();
        Label1.Text =  this.TextBox1.Text.Split(new Char[] { '\n' }, StringSplitOptions.RemoveEmptyEntries).Length.ToString();
        //populateListBox();


    }

关于如何开始这个的简单想法将是一个很大的帮助。感谢

Answer 1

您可以使用Regex

string test = "D; sjhjsd  D; sdsdjks D;";
MatchCollection collection = Regex.Matches(test, @"[D;]+");
var x= collection.Count;

结果：3

此编辑显示如何实现上述Regex以计算每条已知行

protected void btnRead_Click(object sender, EventArgs e)
{
    string text = String.Empty;
    int i = 0;
    int countedChars;
    using (StreamReader stRead = new StreamReader(FileUpload1.PostedFile.InputStream))
    {

        //to write textfile content         
        while (!stRead.EndOfStream)
        {
            var readedLine = stRead.ReadLine() 
            //ListBox1.Items.Add(readedLine );

            if (!string.IsNullOrWhiteSpace(readedLine))
            {
                MatchCollection collection = Regex.Matches(readedLine, @"D;");
                countedChars = collection.Count;
                text += readedLine.Substring(0, readedLine.IndexOf(' ')) +" - "+countedChars + Environment.NewLine;
            }

            i++;
        }
     }

    TextBox1.Text = text;
    //Label1.Text = i.ToString();
    Label1.Text =  this.TextBox1.Text.Split(new Char[] { '\n' }, StringSplitOptions.RemoveEmptyEntries).Length.ToString();
    //populateListBox();


}

Answer 2

使用正则表达式：

    MatchCollection mc = Regex.Matches(lineread, "D;");
int count = mc.Count;

整个功能将是这样的：

string[] lines = System.IO.File.ReadAllLines("file.txt");
string result = "";
for(int i=0;i<lines.Length;i++)
{
    MatchCollection mc = Regex.Matches(lines[i], "D;");
    result+= string.Format("{0} - {1}\r\n", i+1, mc.Count);
}

Answer 3

试试这个：

var pattern = "D";
while (!stRead.EndOfStream)
{
    line+= stRead.ReadLine();

    if (!string.IsNullOrEmpty(line))
    {
        var matches = Regex.Matches(line, @"^\d{4}-\d{2}-(\d{2,3})\sproductkey=([\w;]*)");

        if (matches.Count > 0)
        {
            var day = matches[0].Groups[1].Value;
            var productKey = matches[0].Groups[2].Value;
            var count = Regex.Matches(productKey, pattern).Count;

            text += string.Format("{0} - {1}{2}", day, count, Environment.NewLine);
        } 
    }
}
TextBox1.Text = text;

输出：
01 - 3
02 - 0
03 - 4

您可以根据需要更改模式和日期。例如：

2016-12-07 productkey = D; D; D; 0; 0
  2016-12-11 productkey = Y; Y; Y; 0; 0
  2016-12-25 productkey = D; D; D; D; 0

var pattern = "Y";

输出：
07 - 0
11 - 3
25 - 0

使用ASP.net C＃读取文本文件和操作数据

3 个答案: