Question

我有一个成员表（可以并且应该已经规范化）但它包含以下信息：

**members**
member_id
firstName
lastName
score_1
score_2
score_3
score_4
score_5
score_6
score_7
score_8

我要做的是将所有这些分数加起来，找出哪一个总分是最低分，然后输出成员firstName

我昨天得到的帮助总体上得到了最低价值，但我很难找到一种方法将最终得分改为输出一串成员名称。

$lowScoreResult = $conn->query("SELECT team_members.team_id, team_members.member_id, members.member_id, members.firstName, members.lastName, SUM(members.score_1) `score_1`, SUM(members.score_2) `score_2`, SUM(members.score_3) `score_3`, SUM(members.score_4) `score_4`, SUM(members.score_5) `score_5`, SUM(members.score_6) `score_6`, SUM(members.score_7) `score_7`, SUM(members.score_8) `score_8`
    FROM team_members 
    JOIN members
    ON team_members.member_id = members.member_id
    WHERE members.dashboard_id = $dashboard_id AND team_members.team_id = $teamSelect");


while($row=mysqli_fetch_array($lowScoreResult, MYSQLI_ASSOC)) {
    $low1[] = $row['score_1'];
    $low2[] = $row['score_2'];
    $low3[] = $row['score_3'];
    $low4[] = $row['score_4'];
    $low5[] = $row['score_5'];
    $low6[] = $row['score_6'];
    $low7[] = $row['score_7'];
    $low8[] = $row['score_8'];  
}

$low_score_1 = min($low1);
$low_score_2 = min($low2);
$low_score_3 = min($low3);
$low_score_4 = min($low4);
$low_score_5 = min($low5);
$low_score_6 = min($low6);
$low_score_7 = min($low7);
$low_score_8 = min($low8);

// lowest of the entire set
$t = array($low_score_1,$low_score_2,$low_score_3,$low_score_4,$low_score_5,$low_score_6,$low_score_7,$low_score_8);

所以当前的输出形式是一个数字值，它是来自特定列的超过分数，i，e score_1，score_2等，因为这些列是部门的分数，所以score_1是部门1的部门1 score_2等。 ..我需要一种方式来表示所显示的整体价值来自部门1，如果它来自那里......

Answer 1

我没有在我的控制台上试过它，但它应该让你对caluculatinf有一些了解，在查询本身中字段名称详细信息的得分最低

    select team_members.team_id, team_members.member_id, members.member_id, members.firstName, members.lastName,
    min(score_1),min(score_2),min(score_3),min(score_4),min(score_5),min(score_6),min(score_7),min(score_8)
    from ( select team_members.team_id, team_members.member_id, members.member_id, members.firstName, members.lastName,
            SUM(members.score_1) `score_1`, SUM(members.score_2) `score_2`, SUM(members.score_3) `score_3`, SUM(members.score_4) `score_4`, SUM(members.score_5) `score_5`, SUM(members.score_6) `score_6`, SUM(members.score_7) `score_7`, SUM(members.score_8) `score_8`from
            team_members 
            JOIN members
            ON team_members.member_id = members.member_id
            WHERE members.dashboard_id = $dashboard_id AND team_members.team_id = $teamSelect
     ) as t;

找到最低值和输出用户名

1 个答案: