我的网页上有两个谷歌地图容器。
第一个 - id =" map"只是一个正常的显示地图" 第二个 - id =" map2"是一个搜索地图,用户在输入中键入,地图刷新到用户输入的位置。
这些地图使用相同的api密钥,但它们的回调不同。
如果我在控制台中添加以下两个get和error,说明重复的api调用
<script async defer src="https://maps.googleapis.com/maps/api/js?key=YOUR_API_KEY&callback=initMap" type="text/javascript"></script>
<script async defer src="https://maps.googleapis.com/maps/api/js?key=YOUR_API_KEY&libraries=places&callback=initAutocomplete" type="text/javascript"></script>
但每个地图使用的回调都不同?
那么我如何才能让两张地图都能正常工作呢,因为目前我要么开始工作,要么另一张不能工作
我的代码如下:
<div id="map"></div>
<div id="map2"></div>
<script>
function initMap() {
var paarl = {lat: -33.725853, lng: 18.988628};
var map = new google.maps.Map(document.getElementById('map'), {
zoom: 15,
scrollwheel: false,
center: paarl
});
var marker = new google.maps.Marker({
position: paarl,
map: map
});
}
</script>
<script>
function initAutocomplete() {
var map = new google.maps.Map(document.getElementById('map2'), {
center: {lat: -33.8688, lng: 151.2195},
zoom: 13,
scrollwheel: false,
mapTypeId: 'roadmap'
});
// Create the search box and link it to the UI element.
var input = document.getElementById('pac-input');
var searchBox = new google.maps.places.SearchBox(input);
map.controls[google.maps.ControlPosition.TOP_LEFT].push(input);
// Bias the SearchBox results towards current map's viewport.
map.addListener('bounds_changed', function() {
searchBox.setBounds(map.getBounds());
});
var markers = [];
// Listen for the event fired when the user selects a prediction and retrieve
// more details for that place.
searchBox.addListener('places_changed', function() {
var places = searchBox.getPlaces();
if (places.length == 0) {
return;
}
// Clear out the old markers.
markers.forEach(function(marker) {
marker.setMap(null);
});
markers = [];
// For each place, get the icon, name and location.
var bounds = new google.maps.LatLngBounds();
places.forEach(function(place) {
if (!place.geometry) {
console.log("Returned place contains no geometry");
return;
}
var icon = {
url: place.icon,
size: new google.maps.Size(71, 71),
origin: new google.maps.Point(0, 0),
anchor: new google.maps.Point(17, 34),
scaledSize: new google.maps.Size(25, 25)
};
// Create a marker for each place.
markers.push(new google.maps.Marker({
map: map,
icon: icon,
title: place.name,
position: place.geometry.location
}));
if (place.geometry.viewport) {
// Only geocodes have viewport.
bounds.union(place.geometry.viewport);
} else {
bounds.extend(place.geometry.location);
}
});
map.fitBounds(bounds);
});
}
</script>
<script async defer src="https://maps.googleapis.com/maps/api/js?key=YOUR_API_KEY&callback=initMap" type="text/javascript"></script>
<script async defer src="https://maps.googleapis.com/maps/api/js?key=YOUR_API_KEY&libraries=places&callback=initAutocomplete" type="text/javascript"></script>
答案 0 :(得分:5)
不要使用两个谷歌地图库请求
最简单的方法是在第一个initMap中调用第二个函数
<script>
function initMap() {
var paarl = {lat: -33.725853, lng: 18.988628};
var map = new google.maps.Map(document.getElementById('map'), {
zoom: 15,
scrollwheel: false,
center: paarl
});
var marker = new google.maps.Marker({
position: paarl,
map: map
});
initAutocomplete();
}
</script>
或最终使用onload事件加载第二个