Question

我正在尝试在CURL命令中使用PATCH方法使用-d选项。我的代码如下： IFS =＆＃34; ＆＃34 ;; 读线时做阵列=（$线）;
json_string =＆＃34; {\＆＃34; attributes \＆＃34;：{\＆＃34; member_id \＆＃34;：$ {array [0]}，\＆＃34; is_student \＆＃34 ;：$ {array [1]}}}＆＃34;

  curl -v --fail --silent --show-error --request PATCH -H "Content-Type: application/json"  --user $API_KEY:$API_SECRET -d $json_string $PROFILE_URL/${array[0]} --trace-ascii /dev/stdout
done < $file

输入文件是txt文件，它有两列： 123 0
我使用 space 作为行分隔符。问题是当我使用$ json_string时出现此错误：

    == Info: Rebuilt URL to: "attributes":/
    == Info: Could not resolve host: "attributes"
    == Info: Closing connection 0
    curl: (6) Could not resolve host: "attributes"
    curl: (3) [globbing] unmatched brace in column 1
    == Info: Rebuilt URL to: "member_id":/
    == Info: Could not resolve host: "membe

r_id"
== Info: Closing connection 1
curl: (6) Could not resolve host: "member_id"
== Info: Rebuilt URL to: 123,/
== Info: Could not resolve host: 123,

和

=> Send data, 2 bytes (0x2)
0000: "{
== Info: upload completely sent off: 2 out of 2 bytes

但是当我使用＆＃34; $ json_string＆＃34; （用双引号包围的$ json_string）它工作正常。任何想法？

Answer 1

将变量json_string括在双引号中以防止shell分词：

curl -v --fail --silent --show-error --request PATCH -H "Content-Type:application/json"  --user "$API_KEY:$API_SECRET" -d "$json_string" "$PROFILE_URL/${array[0]}" --trace-ascii /dev/stdout

您可以通过以下方式直接将数据线读入数组：

#!/bin/bash

while read -a line; do
  # your logic
done < "$file"

点击此处了解有关吐痰的更多信息：Bash Best Practices - Quoting

传递给curl的-d选项的Shell变量无法正常工作

1 个答案: