Question

I have been trying to get this to work for a while but can't figure it out. There is an <a> tag inside a <div>. Inside the <a> tag is an <img> This is what the html looks like:

<div class="preview">
    <a class="zoom" href="#"><img src="theimage.jpg" alt="drink"></a>
</div>

My BeautifulSoup code:

divdata = soup2.findAll('div', {"class": "preview"})
for getatag in divdata.find('a', {'class': 'zoom'}):
    for getimgtag in getatag.findAll('img',src=True):
        print getimgtag['src']

Answer 1

您有时会打电话给.find()，有时打电话给.findAll()，这让您感到困惑。您有时会使用for x in y，有时使用x = y来进一步混淆自己。

仅使用for X in findAll()模式：

for divdata in soup2.findAll('div', {"class": "preview"}):
    for getatag in divdata.findAll('a', {'class': 'zoom'}):
        for getimgtag in getatag.findAll('img',src=True):
            print getimgtag['src']

Answer 2

divdata = soup2.findAll('div', {"class": "preview"})

for div in divdata:
    print(div.img.get('src'))

如果您获得了div代码，则.img将获得img代码后代中的下一个div。

如何从<a> tag with a certain class?

2 个答案: