Question

我正在尝试列出通过表单上传的图片的所有文件名，然后通过电子邮件发送。

fileupload.html：

<form method="post" action="upload.php" enctype="multipart/form-data" id="upload" >
<input type="file" name="filesupl[]" multiple id="files" />
<input type="submit" name="UploadBtn" value="Upload" class="formtext" id="UploadBtn">
</form>

upload.php的：

$art_file = $_FILES['filesupl'];
$filecounter = 1;
$count = 0;
foreach ( $art_file as $i => $art_inner ){ 
                    echo $filecounter . ") " . $art_file[$i]['name'] . "<br />"; $filecounter++; 
        }
if ($_SERVER['REQUEST_METHOD'] == 'POST' and isset($_FILES['filesupl']))
    {
        $extension = pathinfo($_FILES['filesupl']['name'], PATHINFO_EXTENSION);

        // Upload files
        // loop all files
        foreach ( $_FILES['filesupl']['name'] as $i => $name )
        {
            // if file not uploaded then skip it
            if ( !is_uploaded_file($_FILES['filesupl']['tmp_name'][$i]) )
                continue;

            // skip large files
            if ( $_FILES['filesupl']['size'][$i] >= $max_size )
                continue;

            // skip unprotected files
            if( !in_array(pathinfo($name, PATHINFO_EXTENSION), $extensions) )
                continue;

            // now we can move uploaded files
            if( move_uploaded_file($_FILES["filesupl"]["tmp_name"][$i], $dir . $name) )
                $count++;
        }

    }

echo json_encode(array('count' => $count));

我尝试了多种方法来访问上传文件的“名称”（上面的代码就是其中一种尝试），但无济于事。

Answer 1

我试图列出上传图片的所有文件名...

如果您的唯一目的是获取上传文件的所有文件名，那么您的代码应该是这样的：

foreach($_FILES['filesupl']['name'] as $name){
    // echo $name . '<br />';
}

现在，如果您想重构代码并使其正常工作，请使用for这样的循环：

$count = count($_FILES['filesupl']['name']);
for($i = 0; $i < $count; ++$i){
    // if file not uploaded then skip it
    if ( !is_uploaded_file($_FILES['filesupl']['tmp_name'][$i]) )
        continue;

    // skip large files
    if ( $_FILES['filesupl']['size'][$i] >= $max_size )
        continue;

    // get file extension
    $extension = pathinfo($_FILES['filesupl']['name'][$i], PATHINFO_EXTENSION);

    // skip unprotected files
    if( !in_array($extension, $extensions) )
        continue;

    // now we can move uploaded files
    if( move_uploaded_file($_FILES["filesupl"]["tmp_name"][$i], $dir . $_FILES['filesupl']['name'][$i])){
        // file has been uploaded
    }
}

echo json_encode(array('count' => $count));

如何从$ _FILES嵌套数组中获取文件名

1 个答案: