我有一个Ourteam应用程序,允许您上传员工的图像,姓名,职位和社交媒体信息。每当我创建一个对象时,都会从media_root中删除“default.jpg”文件。
这是我的模特:
from django.db import models
from cms.models.pluginmodel import CMSPlugin
from django.utils.translation import ugettext_lazy as _
from smartfields import fields
from smartfields.dependencies import FileDependency
from smartfields.processors import ImageProcessor
from django.template.defaultfilters import slugify
class Employee(CMSPlugin):
# Set Name
name = models.CharField(_('name'), max_length=48)
# Define Slug
slug = models.SlugField(max_length=40, null = False, blank = True)
# Set Title
title = models.CharField(_('title'), max_length=48)
# Set Image upload path and image properties
image_upload_path = 'ourteam/%Y/%m/%d'
image = fields.ImageField(upload_to=image_upload_path,
blank=True, default='ourteam/default.jpg',
dependencies=[
FileDependency(processor=ImageProcessor(
format='JPEG', scale={'max_width': 150, 'max_height': 150}))
])
created = models.DateTimeField(_('created'), auto_now_add=True)
email = models.EmailField(_('email'), max_length=254)
# Social Media
twitter = models.CharField(_('twitter'), max_length=24, blank=True, default='https://www.twitter.com')
linkedin = models.CharField(_('linkedin'), max_length=24,blank=True, default='https://www.linkedin.com')
facebook = models.CharField(_('facebook'), max_length=24,blank=True, default='https://www.facebook.com')
class Meta:
verbose_name = _('employee')
verbose_name_plural = _('employee')
db_table = 'employee'
ordering = ('-created',)
get_latest_by = 'created'
def __unicode__(self):
return u'%s' % self.title
def __str__(self):
return self.name
def save(self, *args, **kwargs):
self.slug = slugify(self.name)
super(Employee, self).save(*args, **kwargs)
def get_all_employees():
all_entries = Employee.objects.all().order_by('created')
return all_entries
def slug(sluggy):
sluggy = sluggy.replace(' ', '-').lower()
return slugify(sluggy)
答案 0 :(得分:0)
你应该尝试:
def user_directory_path(instance, filename):
# file will be uploaded to MEDIA_ROOT/user_<id>/<filename>
return 'user_{0}/{1}'.format(instance.user.id, filename)
class MyModel(models.Model):
upload = models.FileField(upload_to=user_directory_path)