Question

我正在尝试将此数组从javascript发送到PHP，但我一直在第3行获取Undefined index：list。此错误来自php文件。

我将提供包括html，javascript和php在内的整个代码。

这是HTML代码。

<!DOCTYPE html>
<html>
<head>
    <meta charset="UTF-8">
    <title></title>
    <script type= "text/javascript" src = "js.js"></script>
</head>
<body>
    <form class = "wall" action="phpf.php"  method="post">
        <label>What is your name</label>
        <input type="text" name ="name" />

        <input type = "submit"  value = "Submit Order" />
    </form>
</body>

这是Javascript代码

$(document).ready(function () {

var list = [34, 56, 23, 90, 43, 58];
$.ajax({
    type: "POST",
    url: "phpf.php",
    data: {'list': JSON.stringify(list)},
    cache: false,
    success: function (response) {
        console.log("This is the list", list);
    }

});
})

这是我在PHP中收到它的地方

<?php

$list = json_decode($_POST['list']);

echo "This is the new list".$list;
?>

我想要有人能帮我。

Answer 1

您无法使用echo打印数组，您应该在php文件中使用print或var_dump：

<?php

$list = json_decode($_POST['list']);

echo "This is the new list";
print_r($list);

我已经验证并且它正在工作，我只是添加jquery，我想你正在js.js中加载文件。但我把我的代码放在这里：

<!DOCTYPE html>
<html>
<head>
<meta charset="UTF-8">
<title></title>

<script type= "text/javascript" src = "https://code.jquery.com/jquery-2.2.4.js"></script>

</head>
<body>
<form class = "wall" action="phpf.php"  method="post">
    <label>What is your name</label>
    <input type="text" name ="name" />

    <input type = "submit"  value = "Submit Order" />
</form>
</body>

<script>
$(document).ready(function() {
   var list = [34, 56, 23, 90, 43, 58];
   $.ajax({
    type: "POST",
    url: "phpf.php",
    data: {'list': JSON.stringify(list)},
    cache: false,
    success: function (response) {
        console.log("This is the list", list);
    }

  });
});
</script>
</html>

使用Ajax将数组从Javascript发送到PHP

1 个答案: