Question

#!/bin/bash
currentTime=$(date +"%R")
currentdate=$(date +'%m/%d/%Y')
oldtime=$(date +%R -d "50 min ago")
echo "Current time : $currentTime"
echo "Current Date : $currentdate"
echo "Old time : $oldtime"
Response=$(curl -X GET -H "Authorization: Basic Token=" "http://targetserver.company.com:8080/v1/organizations/company/environments/environmentname/stats/apis?select=sum(is_error)&timeRange="$currentdate"%20"$currentTime"~"$currentdate"%20"$oldtime"")
echo -e "the response is: \n $Response"

没有得到任何回复？请帮助如何在shell脚本中的curl URL中使用系统日期时间/当前日期时间。

Answer 1

看起来一致，但不完全确定看错了什么。您是否尝试过echo响应行以查看其外观？如何尝试将大括号变量名称包装在大括号中并删除字符串中的引号？

Response=$(curl -X GET -H "Authorization: Basic Token=" "http://targetserver.company.com:8080/v1/organizations/company/environments/environmentname/stats/apis?select=sum(is_error)&timeRange=${currentdate}%20${currentTime}~${currentdate}%20${oldtime}")

如何在shell脚本的curl命令中使用当前日期？

1 个答案: