Question

我有以下需要解析的XML文件，我需要选择person_type值= 1的学生的名字。我在我的java项目中使用dom4j，我无法找到根据person_type的值提取firstname的解决方案。任何帮助将不胜感激。

<?xml version="1.0"?>
<class>
<student>
 <firstname>dinkar</firstname>
 <lastname>kad</lastname>
 <nickname>dinkar</nickname>
 <marks>85</marks>
 <person_types>
  <person_type>1</person_type>
  <person_description>POC</person_description>
 </person_types>
</student>
<student>
 <firstname>Vaneet</firstname>
 <lastname>Gupta</lastname>
 <nickname>vinni</nickname>
 <marks>95</marks>
 <person_types>
  <person_type>1</person_type>
  <person_description>Assistant</person_description>
 </person_types>
</student>
<student>
 <firstname>jasvir</firstname>
 <lastname>singn</lastname>
 <nickname>jazz</nickname>
 <marks>90</marks>
 <person_types>
  <person_type>1</person_type>`
  <person_description>Leader</person_description>
 </person_types>
</student>
</class>

Answer 1

 public static void main(String[] args) {
        try {
           File inputFile = new File("input.txt");
           SAXReader reader = new SAXReader();
           Document document = reader.read( inputFile );

           System.out.println("Root element :" 
              + document.getRootElement().getName());

           Element classElement = document.getRootElement();

           List<Node> nodes = document.selectNodes("/class/student" );
           System.out.println("----------------------------");
           for (Node node : nodes) {
             if("1".equals(node.selectSingleNode("person_types").selectSingleNode("person_type").getText())){
                 System.out.println("\nCurrent Element :" 
                         + node.getName());
                      System.out.println("Student roll no : " 
                         + node.valueOf("@rollno") );
                      System.out.println("First Name : " + node.selectSingleNode("firstname").getText());
                      System.out.println("Last Name : " + node.selectSingleNode("lastname").getText());
                      System.out.println("First Name : " + node.selectSingleNode("nickname").getText());
                      System.out.println("Marks : " + node.selectSingleNode("marks").getText());
             }
           }
        } catch (DocumentException e) {
           e.printStackTrace();
        }
     }

根据条件使用Dom4j解析xml

1 个答案: