我不确定我想要完成的内容是什么，但如果我有这样的数组结构：
[
'owner' => 'Fred',
'cars' => [
0 => [
'model' => 'Toyota',
'passengers' => [
0 => [
'name' => "Tom",
'age' => 35,
'hobbies' => [
0 => [
'name' => 'Chess',
'exp' => 'Master'
],
1 => [
'name' => 'Soccer',
'exp' => 'Novice'
]
]
],
1 => [
'name' => "Bill",
'age' => 30,
'hobbies' => [
0 => [
'name' => 'Basketball',
'exp' => 'Novice'
],
1 => [
'name' => 'Football',
'exp' => 'Expert'
]
]
]
]
]
]
我希望能够基于密钥在模板中进行嵌套替换。因此，对于这个例子，我将有3个模板，＃34;汽车＆＃34;，＆＃34;乘客＆＃34;和爱好＆＃34;。
Model: <<model>> Passengers: <<passengers>>
<<name>> (<<age>>), <<hobbies>>;
<<hobby>> - <<exp>>,
所以我想＆＃34; roll＆＃34;阵列最终只是：
[
'owner' => 'Fred',
'cars' => [
0 => "Model: Toyota, Passengers: Tom (37) Chess - Master, Soccer - Novice; Bill (30) Basketball - Novice, Football - Expert;"
]
]
我一直在努力学习如何走到最深的叶子，以便在更换巢穴后从外面卷起来。
我该怎么做？
答案 0 :(得分：0)
为了构建cars字符串，您需要在每个嵌入式数组上iterate。在下面的示例中，我使用implode来构建passengers和hobbies数组中的字符串：
<?php
$array = array(
'owner' => 'Fred',
'cars' => array(
0 => array(
'model' => 'Toyota',
'passengers' => array(
0 => array(
'name' => "Tom",
'age' => 35,
'hobbies' => array(
0 => array(
'name' => 'Chess',
'exp' => 'Master'
),
1 => array(
'name' => 'Soccer',
'exp' => 'Novice'
)
)
),
1 => array(
'name' => "Bill",
'age' => 30,
'hobbies' => array(
0 => array(
'name' => 'Basketball',
'exp' => 'Novice'
),
1 => array(
'name' => 'Football',
'exp' => 'Expert'
)
)
)
)
)
)
);
$output = array('owner' => '', 'cars' => array());
$output['owner'] = $array['owner'];
foreach ($array['cars'] as $car) {
$output_car = '';
$output_passengers = array();
foreach ($car['passengers'] as $passenger) {
$output_hobbies = array();
foreach ($passenger['hobbies'] as $hobby) {
$output_hobbies[] = $hobby['name'] . ' - ' . $hobby['exp'];
}
$output_passengers[] = $passenger['name'] . ' (' . $passenger['age'] . ') ' . implode(', ', $output_hobbies);
}
$output_car = 'Model: ' . $car['model'] . ', Passengers: ' . implode('; ', $output_passengers);
$output['cars'][] = $output_car;
}
var_dump($output);
将输出：
array (size=2)
'owner' => string 'Fred' (length=4)
'cars' =>
array (size=1)
0 => string 'Model: Toyota, Passengers: Tom (35) Chess - Master, Soccer - Novice; Bill (30) Basketball - Novice, Football - Expert' (length=117)
我对array functions并不熟悉，但我敢打赌解决方案对他们来说可能更简单（或至少更轻）。
答案 1 :(得分：0)
试试这个：
$data = [
['owner' => 'Fred',
'cars' => [
0 => [
'model' => 'Toyota',
'passengers' => [
0 => [
'name' => "Tom",
'age' => 35,
'hobbies' => [
0 => [
'name' => 'Chess',
'exp' => 'Master'
],
1 => [
'name' => 'Soccer',
'exp' => 'Novice'
]
]
],
1 => [
'name' => "Bill",
'age' => 30,
'hobbies' => [
0 => [
'name' => 'Basketball',
'exp' => 'Novice'
],
1 => [
'name' => 'Football',
'exp' => 'Expert'
]
]
]
]
]
]
]
];
$result = [];
foreach ($data as $d) {
$record['owner'] = $d['owner'];
foreach($d['cars'] as $car){
$car_data = "Model: ".$car['model'].", Passengers: ";
$passengers = '';
foreach($car['passengers'] as $p){
$passenger = $p['name']."(".$p['age'].") ";
$i = 0;
$len = count($p['hobbies']);
$hobbies = '';
foreach($p['hobbies'] as $h){
$hobby = '';
if ($i < $len - 1) {
$hobby = $h['name']." - ".$h['exp'].",";
} else if ($i == $len - 1) {
$hobby = $h['name']." - ".$h['exp'];
}
$i++;
$hobbies = $hobbies.$hobby." ";
}
$passenger = $passenger.$hobbies.";";
$passengers = $passengers.$passenger." ";
}
$car_data = $car_data.$passengers;
}
$record['cars'][] = $car_data;
$result[] = $record;
}
print_r($result);
数组（[0] =＆gt;数组（[所有者] =＆gt; Fred [cars] =＆gt;数组（[0] =＆gt;模型： 丰田，乘客：汤姆（35）国际象棋 - 大师，足球 - 新手;法案（30） 篮球 - 新手，足球 - 专家; ）））
答案 2 :(得分：0)
我终于明白了：
function normalizeTemplateVars($vars,$templates) {
$expand_vars = function($parent_key,$parent_value) use($vars,$templates,&$expand_vars) {
if(!is_array($parent_value)) return $parent_value;
$tmp = [];
foreach($parent_value as $item_index => $item_value) {
foreach($item_value as $k => $v) $parent_value[$item_index][$k] = $expand_vars($k,$v);
//mergeAndPurge just replaces variables in template
$tmp[] = mergeAndPurge($parent_value[$item_index],$templates[$parent_key]);
}
return implode($tmp,PHP_EOL);
};
$ret = [];
foreach($vars as $k => $v) $ret[$k] = $expand_vars($k,$v);
return $ret;
}
$replacement_vars = normalizeTemplateVars($vars, ['cars' => '<<owner>> <<cars>>','passengers' => '<<name>> (<<age), <<hobbies>>', 'hobbies' => '<<name>> - <<exp>>']);
这将返回一个只有“汽车”和“所有者”的1级深度数组，这正是我正在寻找的。