Question

所以我正在制作一个基于控制台的文字游戏，以了解更多C＃，但我现在已经陷入困境并且已经诉诸于此。

这可能是一个明显的答案，但我需要另一双眼睛来帮助我。我已经在这里检查了其他问题，他们似乎没有帮助我。

在我的Main()中，我有以下内容：

        int age;

        Console.Write("Before entering the unknown, could you please confirm your age? ");
        age = Convert.ToInt32(Console.ReadLine());
        Console.WriteLine("");

        if (age < 18)
        {
            Console.WriteLine("I'm sorry, you'll now be transferred to a non-explicit version.");
            Console.WriteLine("\n<Press any key to continue>");
            Console.ReadKey();
            Console.Write("\nPlease wait...");
            for (int t = 5; t >= 0; t--)
            {
                Console.CursorLeft = 22;
                Console.Write("{0:00}" + " seconds remaining", t);
                Thread.Sleep(1000);
            }
            Console.WriteLine("");
            Console.WriteLine("\nTo proceed, please press any key...");
            Console.ReadLine();

            NonExplicit();
        }

自我解释。一旦它到达NonExplicit()方法，就会调用以下内容：

        char yes = Console.ReadKey().KeyChar;
        string name;

        Console.WriteLine("\nYou're awake? It's about time. Not old enough, eh? That sucks. \n\nListen, I really need your help. Would you be interested? Y / N");
        Console.ReadKey();

        if (yes == 'y' || yes == 'Y')
        {
            Console.Write("\nYou will?! Wow, That's fantastic. Right then, where shall I start? \nI know! How about telling me your name? ");
            name = Console.ReadKey().ToString();
            Console.WriteLine("\nAhh yes, now you mention it, I certainly remember you, {0}!", name);   
        }
        else
        {
            Console.WriteLine("\nYou don't want to help me? Oh, that's unfortunate... ");
        }

似乎发生的事情是，当＆＃39; y＆＃39;或者＆＃39; Y＆＃39;被迫：

1）要求输入命中以注册上述内容。

2）它同时运行if＆amp; else WriteLines，我认为它与1）一起？

如何修改我的代码，以便在＆＃39; y / Y＆＃39;按下，它读取正确的标准？或者我怎样才能不再需要按Enter键继续？

Answer 1

在您的代码中，在Console.WriteLine("\nTo proceed, please press any key..."); Console.ReadLine();后，您希望在控制台中输入一行（在您按Enter键之前不读取），然后在第二种方法中，您需要尝试再次读取控制台（但这次是单键）。

如果删除第一个Console.ReadLine()？

，会不会有帮助

然后你在询问问题之前（以及在做另一个ReadKey之前）尝试得到是/否答案。

Answer 2

string result = Console.ReadLine();
if (result.ToUpper().Equals("Y"))
  {
     //any thing
  }

Answer 3

使用下面的代码，我测试了它并且它可以工作。

我已将char yes = Console.ReadKey()移至Console.WriteLine()以下我将name = Console.ReadKey()更改为Console.ReadLine()，因为名称超过1个键。

        string name;
        Console.WriteLine("\nYou're awake? It's about time. Not old enough, eh? That sucks. \n\nListen, I really need your help. Would you be interested? Y / N");
        char yes = Console.ReadKey();

        if (yes == 'y' || yes == 'Y')
        {
            Console.Write("\nYou will?! Wow, That's fantastic. Right then, where shall I start? \nI know! How about telling me your name? ");
            name = Console.ReadLine();
            Console.WriteLine("\nAhh yes, now you mention it, I certainly remember you, {0}!", name);
            Console.ReadKey(); // I put this here so the program wouldn't exit
        }
        else
        {
            Console.WriteLine("\nYou don't want to help me? Oh, that's unfortunate... ");
        }

Answer 4

char yes = Console.ReadKey(); // No need for .KeyChar

int age;

Console.Write（＆＃34;在输入未知之前，您能否确认您的年龄？＆＃34;）;   age = Convert.ToInt32（Console.ReadLine（））;   Console.WriteLine（＆＃34;＆＃34）;

可能是

int age = -1
Console.WriteLine("Before entering the unknown, could you please confirm your age? ");
while (age == -1)
{
    if !(int.TryParse(Console.ReadLine(), out age))
    {
        Console.WriteLine("Please enter a valid age");
    }
}

name = Console.ReadKey（）。ToString（）;

应该是

name = Console.ReadLine();

if（yes ==＆＃39; y＆＃39; || yes ==＆＃39; Y＆＃39;）

可能是

if (yes.ToUpper() == "Y")

控制台键盘不工作？

4 个答案: