Question

我有一个表名雇员，它有列FirstName和LastName

现在我想获取表中FirstName和LastName等于值的特定行中的所有数据。

示例：Value = Mark Gabriel

其中：FirstName = Mark LastName = Gabriel

我试过这段代码。

$search = 'Mark Gabriel';

$query = mysqli_query($con,"SELECT * FROM employees WHERE CONCAT(FirstName, ' ', LastName) = '$search' ");
 While($row = mysqli_fetch_array($query)){
     echo $row['FirstName']; }


$query = mysqli_query($con, "SELECT * FROM employees WHERE FirstName LIKE '". $search."%' AND LastName LIKE '" .$search. "%' ");
  While($row = mysqli_fetch_array($query)){
     echo $row['FirstName'];
 }

我没有从我试过的查询中得到任何回复。

任何评论都表示赞赏。谢谢

Answer 1

你可以尝试一下：

SELECT *, CONCAT(firstName, ' ', lastName) as search FROM employees HAVING search = '$search'

如何选择2个字符串列的组合等于该值的行

1 个答案: