SQL：具有特定值的行数（动态）

Question

这里很难解释问题：）

我需要获得一个新列，我有大量的行 F.E.“RIT-17000263-T：1”将有一个额外的列“Total Sequences”：'9' “RIT-17000264-T：1”将是“总序列”：'2'

欢迎任何帮助！：

SELECT DISTINCT
    CONCAT(R.[Trip No_],'-', CONCAT('T: ', LEFT(R.[Partial trip Line No_],1))) AS 'TRIP',
    R.[File] AS 'FILE',
    R.[Sequence No_] AS 'SEQUENCE IN PTRIP'
FROM            
    [Route] AS R
WHERE           
    (R.[Trip No_] = 'RIT-17000263' 
     OR R.[Trip No_] = 'RIT-17000264')
GROUP BY 
    CONCAT(R.[Trip No_], '-', CONCAT('T: ', LEFT(R.[Partial trip Line No_],1))), 
    R.[File], R.[Sequence No_]

Answer 1

也许将它包装在CTE中......

with cte as(
    SELECT DISTINCT
    CONCAT(R.[Trip No_],'-', CONCAT('T: ', LEFT(R.[Partial trip Line No_],1))) AS 'TRIP',
    R.[File] AS 'FILE',
    R.[Sequence No_] AS 'SEQUENCE IN TRIP'
FROM            
    [Route] AS R
WHERE           
    (R.[Trip No_] = 'RIT-17000263' 
     OR R.[Trip No_] = 'RIT-17000264')
GROUP BY 
    CONCAT(R.[Trip No_], '-', CONCAT('T: ', LEFT(R.[Partial trip Line No_],1))), 
    R.[File], R.[Sequence No_])

select
    c.TRIP,
    c.[FILE],
    c.[SEQUENCE IN TRIP],
    c2.CT as [Total Sequences]
from 
    cte c
    join (select TRIP, count(TRIP) as CT from cte group by TRIP) c2 on c2.TRIP = c.TRIP