R：ggplot显示x轴上的所有日期

Question

我有以下数据集

structure(list(Date = structure(c(16636, 16667, 16698, 16728, 
16759, 16789, 16820, 16851, 16880, 16911, 16636, 16667, 16698, 
16728, 16759, 16789, 16820, 16851, 16880, 16911, 16636, 16667, 
16698, 16728, 16759, 16789, 16820, 16851, 16880, 16911, 16636, 
16667, 16698, 16728, 16759, 16789, 16820, 16851, 16880, 16911, 
16636, 16667, 16698, 16728, 16759, 16789, 16820, 16851, 16880, 
16911), class = "Date"), Wheel = structure(c(5L, 5L, 5L, 5L, 
5L, 5L, 5L, 5L, 5L, 5L, 12L, 12L, 12L, 12L, 12L, 12L, 12L, 12L, 
12L, 12L, 9L, 9L, 9L, 9L, 9L, 9L, 9L, 9L, 9L, 9L, 11L, 11L, 11L, 
11L, 11L, 11L, 11L, 11L, 11L, 11L, 6L, 6L, 6L, 6L, 6L, 6L, 6L, 
6L, 6L, 6L), .Label = c("L1", "L2", "L3", "L4", "L5", "L6", "R1", 
"R2", "R3", "R4", "R5", "R6"), class = "factor"), WearRate = c(-0.000367, 
0, 0, 0, 0.001888, 0, -0.00018, 0.000579, -0.000211, 0.000643, 
0.000106, 0, 0, 0, 0.000833, 0, -0.00036, 0.000811, -0.000819, 
0.002044, -0.00029, 0, 0, 0, 0.001666, 0, -0.000348, 0.000888, 
-0.000679, 0.001636, 8.7e-05, 0, 0, 0, 0.000666, 0, -0.000315, 
0.000618, -0.000585, 0.001636, -0.000512, 0, 0, 0, 0.002499, 
0, -0.000247, 0.000734, -9.4e-05, 0.000409)), .Names = c("Date", 
"Wheel", "WearRate"), row.names = 211269:211318, class = "data.frame")

我正在制作Date vs WearRate和color by Wheel的情节。代码如下：

ggplot(data = df) + geom_point(mapping = aes(x = Date, y = WearRate, color = Wheel))

它有效，但我想放置实际的日期标签。我该怎么做？

修改

目前的情节如下图所示。但是，我希望看到＆＃34; 2015年8月＆＃34;，＆＃34; 2015年9月＆＃34; X轴上的等等，我想显示所有的刻度。

Answer 1

最简单的方法是使用scale_x_date

ggplot(data = df) + 
  geom_point(mapping = aes(x = Date, y = WearRate, color = Wheel))+
  scale_x_date(date_labels="%b %y",date_breaks  ="1 month")

%b：缩写的月份名称
%y：没有世纪的年份 有关完整可能性的说明，请参阅?strftime()