Question

目前正在努力从头开始学习Python 3.5并彻底享受这个过程。最新的事情是编写一个执行以下操作的基本程序..

要求用户考虑1到100之间的数字
猜猜它是什么
要求用户输入“1”（如果太低），“3”（如果太高）和“2”（如果）正确
根据该用户输入提供新号码
在羞辱退出前将自己限制为10次尝试
庆祝它正确的时候

现在我认为我已经完成所有工作减去更高/更低的功能。我的问题是这个。

注意这与该主题的其他问题不同，因为我不想为PC输入任何数字来处理。还希望生成伪随机数，其被限制在给定值内，以用于来自PC的后续猜测。不增加。

“我如何实现一个查看var' guess'的功能，并根据用户输入将其修改为更高或更低，同时保持高于0且低于100”。

代码：

import random  

print("\tWelcome to the psychic computer")
print("\nI want you to think of a number between 1 and 100.")
print("I will try to guess it in 10 or less tries.\n")
print("\n Press 1 for a lower guess, 3 for a higher one and 2 if I get it       right\n")

tries = int(1)

guess = random.randint(1, 100)
print("\nI guess ", + guess, " Is this correct?")


while tries < 10:
    feedback = int (input("\nEnter 1 if too high, 3 if too low or 2 if bang   on\n\n"))
    tries += 1
    if feedback == 1:
        print("Balls! Guess I need to go Higher will", + guess, + "do?")

    elif feedback == 3:
        print("\nSh*te! Lower it is then...")

    elif feedback == 2:
        print("YEEAAAHH BOYEEEE! Told you I was phychic.")
        input("\nHit enter to quit")
        end

    elif feedback != (1,2,3):
        print("Not a valid guess. Try again.")
        break

    if tries >= 9:
        print("\nSh*t, guess I'm not so psychic after all")
    input("\nHit enter to exit")

Answer 1

你可以做类似二元搜索的事情。使用low_number和high_number通过取两者的中间值来计算猜测。这些最初可以设置为0和100.您还应该跟踪上次猜测。如果你的上次猜测太低，你可以将你的low_number设置为等于猜测+ 1。如果您的上一次猜测太高，可以将您的high_number设置为该guess-1。

Answer 2

好的，这是我到目前为止所拥有的。它的工作原理是它将根据用户输入以（半）随机更高或更低的猜测进行响应，但尚未将原始猜测存储为参考。我明天会看。再次感谢您的建议。

BTW一旦工作，我打算使用数学，并提出一个解决方案，总是在x次尝试中正确...

    import random  

    print("\tWelcome to the psychic computer")
    print("\nI want you to think of a number between 1 and 100.")
    print("I will try to guess it in 10 or less tries.\n")
    print("\n Press 1 for a higher guess, 3 for a lower one and 2 if I get it    right\n")

    tries = int()
    guess = random.randint(1, 100)
    high_number = int(100 - guess)
    low_number = int(1 + guess)

    print("\nI guess ", + guess, " Is this correct?")

    while tries < 10:

    feedback = int (input("\nEnter 1 to go higher, 3 to go lower or 2 if bang    on\n\n"))
    tries += 1
    if feedback == 1:
        guess = random.randint(high_number, 100)
        print("Balls! Guess I need to go Higher how about", + guess)

        elif feedback == 3:
            guess = random.randint(1, low_number)
            print("\nSh*te! Lower it is then... what about", + guess)    

        elif feedback == 2:
            print("YEEAAAHH BOYEEEE! Told you I was phychic.")
            input("\nHit enter to quit")
            end

        elif feedback != (1,2,3):
            input("Not a valid guess. Try again.")
            break

if tries >= 9:
    print("\nSh*t, guess I'm not so psychic after all")
input("\nHit enter to exit")

存储数字并根据用户输入进行比较

2 个答案: