大家好日子, 我想删除List<>中的对象的属性和属性名称。从另一个对象(作为属性)返回时。
我有以下课程:
public class Base {
protected String type;
public String getType() {
return type;
}
public void setType(String type) {
this.type = type;
}
}
public class A extends Base {
private double[] value;
public A() { type = "A"; }
public A(double[] value) {
this();
setValue(value);
}
public double[] getValue() {
return value;
}
public void setValue(double[] value) {
this.value = value;
}
}
public class B extends Base {
private List<A> value = new ArrayList<A>();
public B() { type = "B"; }
public B(List<A> value) {
this();
setValue(value);
}
public List<A> getValue() { return value; }
public void setValue(List<A> value) {
this.value = value;
}
}
public class C extends Base {
private List<B> value = new ArrayList<B>();
public C() { type = "C"; }
public List<B> getValue() {
return value;
}
public void setValue(List<B> value) {
this.value = value;
}
}
并使用它们:
A a = new A();
a.setValue(new double[]{1,2});
B b = new B();
List<A> aList = new ArrayList<A>();
aList.add(new A(new double[]{1,2}));
aList.add(new A(new double[]{3,4}));
b.setValue(aList);
C c = new C();
List<B> bList = new ArrayList<B>();
List<A> aList1 = new ArrayList<A>();
List<A> aList2 = new ArrayList<A>();
aList1.add(new A(new double[]{1,2}));
aList1.add(new A(new double[]{3,4}));
aList2.add(new A(new double[]{5,6}));
bList.add(new B(aList1));
bList.add(new B(aList2));
c.setValue(bList);
ObjectMapper jsonMapper = new ObjectMapper();
jsonMapper.enable(SerializationFeature.INDENT_OUTPUT);
try {
System.out.println("=== com.example.A ===");
System.out.println(jsonMapper.writeValueAsString(a));
System.out.println("=== com.example.B ===");
System.out.println(jsonMapper.writeValueAsString(b));
System.out.println("=== com.example.C ===");
System.out.println(jsonMapper.writeValueAsString(c));
} catch (JsonProcessingException e) {
e.printStackTrace();
}
我得到的地方:
=== com.example.A ===
{
"type" : "A",
"value" : [ 1.0, 2.0 ]
}
=== com.example.B ===
{
"type" : "B",
"value" : [ {
"type" : "A",
"value" : [ 1.0, 2.0 ]
}, {
"type" : "A",
"value" : [ 3.0, 4.0 ]
} ]
}
=== com.example.C ===
{
"type" : "C",
"value" : [ {
"type" : "B",
"value" : [ {
"type" : "A",
"value" : [ 1.0, 2.0 ]
}, {
"type" : "A",
"value" : [ 3.0, 4.0 ]
} ]
}, {
"type" : "B",
"value" : [ {
"type" : "A",
"value" : [ 5.0, 6.0 ]
} ]
} ]
}
但我希望如此:
=== com.example.A ===
{
"type" : "A",
"value" : [ 1.0, 2.0 ]
}
=== com.example.B ===
{
"type" : "B",
"value" : [ [ 1.0, 2.0 ], [ 3.0, 4.0 ] ]
}
=== com.example.C ===
{
"type" : "C",
"value" : [ [ [ 1.0, 2.0 ], [ 3.0, 4.0 ] ], [ [ 5.0, 6.0 ] ] ]
}
我能够删除该属性&#34;输入&#34;当从B和财产&#34;类型&#34;返回时A来自C的B使用:
@JsonIgnoreProperties( { "type" })
public List<A> getValue() {
return value;
}
...
@JsonIgnoreProperties( { "type" })
public List<B> getValue() {
return value;
}
但我仍然得到了财产&#34;价值&#34;名字和花括号......
=== com.example.A ===
{
"type" : "A",
"value" : [ 1.0, 2.0 ]
}
=== com.example.B ===
{
"type" : "B",
"value" : [ {
"value" : [ 1.0, 2.0 ]
}, {
"value" : [ 3.0, 4.0 ]
} ]
}
=== com.example.C ===
{
"type" : "C",
"value" : [ {
"value" : [ {
"value" : [ 1.0, 2.0 ]
}, {
"value" : [ 3.0, 4.0 ]
} ]
}, {
"value" : [ {
"value" : [ 5.0, 6.0 ]
} ]
} ]
}
我可以使用什么注释来获得所需的输出?或者我是否需要重新设计课程?
答案 0 :(得分:0)
修改B和C类,如下所示:
为值添加@JsonIgnore
注释以避免打印值并创建一个返回类型为getValueForJson()
的新方法List<double[]>
,其输出为深度解析结果,其值为{{1} }。这个新方法添加了注释A
,其值为@JsonProperty
,以便将其视为名为"value"
的成员。
value
答案 1 :(得分:0)
public class A extends Base {
private double[] value;
public A() {
type = "A";
}
public A(double[] value) {
this();
setValue(value);
}
public double[] getValue() {
return value;
}
public void setValue(double[] value) {
this.value = value;
}
}
public class B extends Base {
private List<A> value = new ArrayList<A>();
public B() {
type = "B";
}
public B(List<A> value) {
this();
setValue(value);
}
@JsonIgnoreProperties({"type"})
public List<A> getValue() {
return value;
}
@JsonGetter("value")
@JsonIgnoreProperties({"type"})
public List<double[]> getA() {
List<double[]> res = new ArrayList<>();
for (A a : value) {
res.add(a.getValue());
}
return res;
}
public void setValue(List<A> value) {
this.value = value;
}
@Override
public String toString() {
return "" + value;
}
}
public class C extends Base {
private List<B> value = new ArrayList<B>();
public C() {
type = "C";
}
@JsonGetter("value")
@JsonIgnoreProperties({"type"})
public List<List<double[]>> getB() {
List<List<double[]>> res1 = new ArrayList<>();
for (B b : value) {
List<double[]> res2 = new ArrayList<>();
for (A a : b.getValue()) {
res2.add(a.getValue());
}
res1.add(res2);
}
return res1;
}
public List<B> getValue() {
return value;
}
public void setValue(List<B> value) {
this.value = value;
}
}