我有一个不同颜色的图像的无序列表,我希望它随机选择2个图像并转到另一个列表,我知道appendTo和Math.Random会做的伎俩但我不知道如何实现它可以你帮我吗?
这里是小提琴和代码
<div class="row">
<div class="col-md-6">
<ul class="imageList">
<li><img class="swapimage" src="https://dummyimage.com/200x200/000/fff" alt=""></li>
<li><img class="swapimage" src="https://dummyimage.com/200x200/ffaa00/fff" alt=""></li>
<li><img class="swapimage" src="https://dummyimage.com/200x200/ff00d5/fff" alt=""></li>
<li><img class="swapimage" src="https://dummyimage.com/200x200/30c7db/fff" alt=""></li>
</ul>
</div>
<div class="col-md-6">
<ul class="randomList">
<li></li>
<li></li>
<li></li>
<li></li>
</ul>
</div>
</div>
<input class="main-button" type="button" value="swap" id="swapBtn" name="swapBtn">
$('#swapBtn').on('click', function(){
$('.swapimage').prependTo('.randomList li');
});
答案 0 :(得分:0)
有点晚了......带了这个新手一段时间。我将如何做到这一点:
len = $(".swapimage").length
$('#swapBtn').on('click', function(){
number = Math.floor(Math.random() * len);
do {
number2 = Math.floor(Math.random() * len);
} while (number2 == number);
$('.randomList li').eq(number).replaceWith( $('.swapimage').eq(number) )
$('.randomList li').eq(number2).replaceWith( $('.swapimage').eq(number2) )
});
.imageList { margin-bottom: 100px; }
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.0/jquery.min.js"></script>
<input class="main-button" type="button" value="swap" id="swapBtn" name="swapBtn">
<div class="row">
<div class="col-md-6">
<ul class="imageList">
<li><img class="swapimage" src="https://dummyimage.com/200x200/000/fff" alt=""></li>
<li><img class="swapimage" src="https://dummyimage.com/200x200/ffaa00/fff" alt=""></li>
<li><img class="swapimage" src="https://dummyimage.com/200x200/ff00d5/fff" alt=""></li>
<li><img class="swapimage" src="https://dummyimage.com/200x200/30c7db/fff" alt=""></li>
</ul>
</div>
<div class="col-md-6">
<ul class="randomList">
<li></li>
<li></li>
<li></li>
<li></li>
</ul>
</div>
</div>