Question

我希望能够从result_array（）查询中获取值以在另一个查询中使用。

/// <remarks/>
[System.CodeDom.Compiler.GeneratedCodeAttribute("xsd", "4.6.1055.0")]
[System.SerializableAttribute()]
[System.Diagnostics.DebuggerStepThroughAttribute()]
[System.ComponentModel.DesignerCategoryAttribute("code")]
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType=true)]
public partial class RequestCheckIssueAddressAddressLine {

    private adrLn addrLineTypCdField;

    private bool addrLineTypCdFieldSpecified;

    /// <remarks/>
    [System.Xml.Serialization.XmlAttributeAttribute()]
    public adrLn AddrLineTypCd {
        get {
            return this.addrLineTypCdField;
        }
        set {
            this.addrLineTypCdField = value;
        }
    }

    /// <remarks/>
    [System.Xml.Serialization.XmlIgnoreAttribute()]
    public bool AddrLineTypCdSpecified {
        get {
            return this.addrLineTypCdFieldSpecified;
        }
        set {
            this.addrLineTypCdFieldSpecified = value;
        }
    }
}

我希望能够遍历数组中的每个项目并返回要在where子句中使用的值（例如10,11,12）。

Array ( [0] => Array ( [taskID] => 10 ) [1] => Array ( [taskID] => 11 ) [2] => Array ( [taskID] => 12 ) )是数组，$task是数组中的项目。

$t

错误：

错误号码：1054

未知列＆＃39;数组＆＃39;在＆＃39; where子句＆＃39;

SELECT foreach($task as $t){ $this->db->select('roleID'); $this->db->from('project_tasks'); $this->db->where('taskID', $t); //ERROR line 287 } FROM roleID WHERE project_roles = taskID

文件名：models / Project_model.php

行号：287

Answer 1

foreach($task as $t){
    $this->db->select('roleID');
    $this->db->from('project_tasks');
    $this->db->where('taskID', $t['taskID']);
}

Answer 2

您忘记了$task是一个数组数组：

foreach($task as $t){
    $this->db->select('roleID');
    $this->db->from('project_tasks');
    $this->db->where('taskID', $t['taskID']); 
}

从result_array（）中提取其类型的值

2 个答案: