[
{
"c_name" : "r",
"email_id" : "r",
"phn_no" : "2",
"c_id" : "1"
},
{
"c_name" : "e",
"email_id" : "e",
"phn_no" : "4",
"c_id" : "2"
}
]
这是我作为JSON字符串收到的输出。现在我该如何访问这些数据?我使用了NSJSONSerialization
类:
NSError *writeError = nil;
NSData *jsonData = [NSJSONSerialization dataWithJSONObject:arr_mcontacts options:NSJSONWritingPrettyPrinted error:&writeError];
NSString *jsonString = [[NSString alloc] initWithData:jsonData encoding:NSUTF8StringEncoding];
NSLog(@"JSON Output: %@",jsonString);
答案 0 :(得分:1)
我认为你有一系列词典。这样的事情应该有效:
NSError *writeError;
NSError *error;
NSData *jsonData = [jsonString dataUsingEncoding:NSUTF8StringEncoding];
NSMutableArray *arrayOfDictionary = [[NSMutableArray alloc] init];
arrayOfDictionary = [NSJSONSerialization JSONObjectWithData:jsonData options:NSJSONReadingMutableContainers error:nil];
NSDictionary *dictionary = [myArray objectAtIndex:0];
NSString *valueString= [dictionary objectForKey: @"c_name"];
答案 1 :(得分:0)
要访问数据,请使用字典而不是字符串。以下代码显示
NSDictionary *responseDict=[NSJSONSerialization JSONObjectWithData: jsonData options:NSJSONReadingMutableContainers error:&error]; for(NSArray *a in responseDict)
{[cnamearray addobject [a valueforKey:@"c_name"]];
}NSLog(@"The cnamearray contains:", cnamearray);
输出将是cnamearray包含:{r,e}