Question

我希望在用户进入页面时创建一个运行jQuery脚本的页面，即使用户离开页面或关闭浏览器，查询也会运行。这可能吗？

if(localStorage.getItem("counter")){
  if((localStorage.getItem("counter") >= 300) || (localStorage.getItem("counter") <= 0)){
    var value = 300;
  }else{
    var value = localStorage.getItem("counter");
  }
}else{
  var value = 300;
}
document.getElementById('divCounter').innerHTML = value;

var counter = function (){
  if(value <= 0){
    localStorage.setItem("counter", 0);
    value = 0;
    $( ".exit" ).trigger( "click" );
  }else{
    value = parseInt(value)-1;
    localStorage.setItem("counter", value);
  }
  document.getElementById('divCounter').innerHTML = value;
};

var interval = setInterval(function (){counter();}, 1000);

这是我的剧本。有关详细信息，这是300的倒计时，当用户进入页面时，即使用户离开页面直到达到0，我也希望它能够运行。

Answer 1

我敢回答你的问题，但希望这会对你有所帮助。此选项卡关闭后，没有机会运行此js代码，但您可以通过设置每个间隔周期和用户设置的 time_leave 来记住用户离开您网站的时间使用onbeforeunload离开您的网站：

var value;
if (localStorage.getItem('counter')) {
  if ((localStorage.getItem('counter') >= 300) || (localStorage.getItem('counter') <= 0)) {
    value = 300;
  } else {
    value = getElaspedTime();
  }
} else {
  value = 300;
}

document.getElementById('divCounter').innerHTML = value;

var counter = function () {
  if (value <= 0) {
    localStorage.setItem('counter', 0);
    value = 0;
    //$('.exit').trigger('click');
  } else {
    value = parseInt(value) - 1;
    localStorage.setItem('counter', value);
  }
  document.getElementById('divCounter').innerHTML = value;
  // set "departure"-time
  localStorage.setItem('time_leave', (new Date()).getTime());
};

function getElaspedTime() {
  var now = new Date();
  var timeLeft = + localStorage.getItem('time_leave');
  timeLeft = new Date(timeLeft);
  var passedSecs = (now.getTime() - timeLeft.getTime()) / 1000;
  return parseInt(localStorage.getItem('counter')) - parseInt(passedSecs);
}

window.onbeforeunload = function(){
  // set "departure"-time when user closes the tap
  localStorage.setItem('time_leave', (new Date()).getTime());
};

var interval = setInterval(function () {
  counter();
}, 1000);

即使用户离开了页面，jQuery也会继续

1 个答案: