Question

如何按降序对此列表进行排序？

timestamp = [
    "2010-04-20 10:07:30",
    "2010-04-20 10:07:38",
    "2010-04-20 10:07:52",
    "2010-04-20 10:08:22",
    "2010-04-20 10:08:22",
    "2010-04-20 10:09:46",
    "2010-04-20 10:10:37",
    "2010-04-20 10:10:58",
    "2010-04-20 10:11:50",
    "2010-04-20 10:12:13",
    "2010-04-20 10:12:13",
    "2010-04-20 10:25:38"
]

Answer 1

在一行中，使用lambda：

timestamp.sort(key=lambda x: time.strptime(x, '%Y-%m-%d %H:%M:%S')[0:6], reverse=True)

将函数传递给list.sort：

def foo(x):
    return time.strptime(x, '%Y-%m-%d %H:%M:%S')[0:6]

timestamp.sort(key=foo, reverse=True)

Answer 2

这将为您提供数组的排序版本。

sorted(timestamp, reverse=True)

如果您想就地排序：

timestamp.sort(reverse=True)

Answer 3

你可以这样做：

timestamp.sort(reverse=True)

Answer 4

由于您的列表已按升序排列，我们可以简单地撤消列表。

>>> timestamp.reverse()
>>> timestamp
['2010-04-20 10:25:38', 
'2010-04-20 10:12:13', 
'2010-04-20 10:12:13', 
'2010-04-20 10:11:50', 
'2010-04-20 10:10:58', 
'2010-04-20 10:10:37', 
'2010-04-20 10:09:46', 
'2010-04-20 10:08:22',
'2010-04-20 10:08:22', 
'2010-04-20 10:07:52', 
'2010-04-20 10:07:38', 
'2010-04-20 10:07:30']

Answer 5

你简单的类型：

timestamp.sort()
timestamp=timestamp[::-1]

Answer 6

这是另一种方式


timestamps.sort()
timestamps.reverse()
print(timestamps)

Python列表按降序排序

6 个答案: