我正在调用SOAP Web服务,该服务返回类似于此的XML:
<?xml version="1.0" encoding="UTF-8"?>
<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<soapenv:Body>
<SalidaConsultaSAF xmlns="http://wtp">
<coderror>02</coderror>
<dserror>No records</dserror>
</SalidaConsultaSAF>
</soapenv:Body>
</soapenv:Envelope>
我试图解析它以便访问代码coderror
和dserror
的值,但我只是一直惨遭失败。
这只是我采取的几种方法之一:
# parse XML response
from xml.etree import ElementTree as ET
# call the web service
response = requests.post(url, auth=('myUser', 'myPass'),
verify=False, data=body, headers=headers)
tree = ET.ElementTree(ET.fromstring(response.content))
a_ = ET.Element(tree) # ==> {'attrib': {}, 'tag': <xml.etree.ElementTree.ElementTree object at 0x7f4736e299d0>, '_children': []}
b_ = ET.SubElement(a_, 'coderror') # ==> {'attrib': {}, 'tag': 'soapenv', '_children': []}
如您所见,变量b
的值为&#34;为空&#34;。我想获得字符串02
。
请帮忙吗?
答案 0 :(得分:2)
import xml.etree.ElementTree as ET
tree = ET.XML(response.content)
tree.findtext(".//{http://wtp}SalidaConsultaSAF/{http://wtp}coderror")
收益'02'
。
XPath是你的朋友。