我正在尝试使用表单允许用户将图像上传到我的Django项目中存储在数据库中的项目,但是,我正在获得控制台输出,告诉我formset
我正在使用无效......
我尝试用来将图像上传到项目的视图已定义为:
def upload_budget_pdfs(request, project_id):
project = Project.objects.get(id=project_id)
print("Value of project in 'upload_budget_pdfs()': ", project)
presentations = project.budget_versions.select_related('meeting').prefetch_related('budget_items', 'cci_items', 'presenters').filter(version_number__isnull=False).annotate(vn=F('version_number') * -1).order_by('presentation_date', 'created', '-vn')
print("Value of presentations in 'upload_budget_pdfs()': ", presentations)
drawing_formset = DrawingUploadFormset(prefix="drawings", queryset=Drawing.objects.filter(budget__in=presentations).order_by('budget__presentation_date', 'budget__created'))
print("Value of drawing_formset in 'upload_budget_pdfs()': ", drawing_formset)
if drawing_formset.is_valid():
print 'Saving drawing_formset'
print "Before", [b.id for b in project.budget_versions.all()]
for drawing_form in drawing_formset:
if drawing_form.instance.budget:
print 'Instance', drawing_form.instance.budget
drawing = drawing_form.save(commit=False)
drawing.budget = drawing_form.instance.budget
drawing.save()
print drawing, [b.id for b in project.budget_versions.all()]
else: print 'Drawing formset not valid.',drawing_formset.errors
budget_formset = BudgetPresentationFormset(request.POST, request.FILES, instance=project, prefix="presentations")
if budget_formset.is_valid() and budget_formset.has_changed():
updated_budget_presentations = budget_formset.save()
elif budget_formset.has_changed(): print 'Budget formset not valid.',budget_formset.errors
return HttpResponseRedirect(reverse('projects:concept', args=[project_id]))
和调用此视图时我得到的控制台输出是:
(“'upload_budget_pdfs()':”项目的价值,<项目:测试1>)
(“'upload_budget_pdfs()'中的演示文稿的价值:”,[&lt;预算:测试1:版本-1&gt;,&lt;预算:测试1:版本-1&gt;,&lt;预算:测试1 :版本0&gt;,&lt;预算:测试1:版本0&gt;,,,,,,,,,,,,,,,,'...(其余元素被截断)...'])< / p>
(“upload_budget_pdfs()'中的drawing_formset的值:”,&lt; django.forms.formsets.DrawingFormFormSet对象位于0x10cee3790&gt;)
绘图formset无效。 []
所以很清楚,我视图中的else
语句是在这里运行的,但我不确定为什么,因为控制台清楚地表明变量都保存了正确的数据... < / p>
我在这里初始化drawing_formset
变量的方式有什么问题? queryset
我传入DrawingUploadFormset(...)
是否正确? is_valid()
实际检查了什么?
修改
我在接受的答案中做了更改,以便我现在宣布drawing_formset
:
drawing_formset = DrawingUploadFormset(request.POST, request.FILES, prefix="drawings", queryset=Drawing.objects.filter(budget__in=presentations).order_by('budget__presentation_date', 'budget__created'))
但似乎我现在收到了“内部服务器错误”并且MultiValueDictKeyError
就行了:
for drawing_form in drawing_formset: #This line is what's causing the MultiValueDictKeyError
我不明白为什么会这样?有什么建议吗?
答案 0 :(得分:3)
您的formset不包含任何数据。您需要将request.POST
和request.FILES
作为第一个和第二个参数(或data
和files
关键字参数),但前提是它是实际的表单提交。
如果没有数据传递到表单或表单集,则会将其视为未绑定,并且将在不检查错误的情况下返回False
。
通常的模式是在request.method == 'POST'
时传递它们,然后验证formset:
def upload_budget_pdfs(request, project_id):
...
if request.method == 'POST':
drawing_formset = DrawingUploadFormset(request.POST, request.FILES, prefix='drawings', queryset=...)
if drawing_formset.is_valid():
# save formset
return HttpResponseRedirect(...)
else:
drawing_formset = DrawingUploadFormset(prefix='drawings', queryset=...)
return render(...) # Render formset
这将在GET上显示一个空白表单,这是一个填写表单,在提交失败时会显示错误消息,它将保存表单集并重定向成功提交。