Question

我正在尝试从下面发布的id文件中获取name，pin和xml，然后我编写了以下发布的代码。问题是，这一行node.getNodeValue()总是返回

请告诉我如何正确地从id文件中获取name，pin和xml？

码

try {
            URL url = new URL(link);
            URLConnection conn = url.openConnection();

            DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
            DocumentBuilder builder = factory.newDocumentBuilder();
            Document doc = builder.parse(conn.getInputStream());

            doc.getDocumentElement().normalize();

            NodeList nodes = doc.getElementsByTagName("employee");

            Log.i(TAG, " nodeLength:" + nodes.getLength());


            for (int i = 0; i < nodes.getLength(); i ++) {
                Node node = nodes.item(i);
                Log.i(TAG, "Current Element :" + node.getNodeValue());//THIS LINE
            }

        }
        catch (Exception e) {
            e.printStackTrace();
        }

XML

<employee_list>
<employee id="21358" pin="0000" name="www"/>
<employee id="21359" pin="0011" name="qqq"/>
<employee id="20752" pin="1011" name="Test"/>
<employee id="814" pin="1012" name="Pf"/>
<employee id="21372" pin="1013" name="Kru"/>
</employee_list>

堆栈跟踪

01-24 15:05:54.219 5624-5718/com.example. I/XmlParser:  nodeLength:33
01-24 15:05:54.220 5624-5718/com.example. I/XmlParser: Current Element :null
01-24 15:05:54.220 5624-5718/com.example. I/XmlParser: Current Element :null
01-24 15:05:54.220 5624-5718/com.example. I/XmlParser: Current Element :null
01-24 15:05:54.220 5624-5718/com.example.I/XmlParser: Current Element :null
01-24 15:05:54.220 5624-5718/com.example. I/XmlParser: Current Element :null

Answer 1

您可以获取所有NamedNodeMap的{{1}}并使用Attributes作为此getNamedItem的{{1}}作为此函数的关键，最后使用Id,pin,name函数<获取值/ p>

getNodeValue

输出：

     NodeList nodes = doc.getElementsByTagName("employee");
     for (int i = 0; i < nodes.getLength(); i ++) {
         Node node = nodes.item(i);
         NamedNodeMap attr =  node.getAttributes();

         // find item using key name and then fetch the node value
         String id = attr.getNamedItem("id").getNodeValue();
         String pin = attr.getNamedItem("pin").getNodeValue();
         String name = attr.getNamedItem("name").getNodeValue();    
         System.out.println(id+" "+pin+" "+name);
     }

或者您也可以使用循环而不是获取单个值

21358 0000 www
21359 0011 qqq
20752 1011 Test
814 1012 Pf
21372 1013 Kru

解析android中的xml文件，获取给定节点的所有属性

1 个答案: