Question

=”“

这是JsonObjectRequest，我收到了错误消息。帮助我......

Map<String, String> jsonParams = new HashMap<String, String>();
jsonParams.put("email",email.getText().toString());

JsonObjectRequest jsonObjectRequest=new JsonObjectRequest(Request.Method.POST, json_url, new JSONObject(jsonParams), new Response.Listener<JSONObject>() {
        @Override
        public void onResponse(JSONObject response) {
            try {
                Log.d("Response", response.toString());
                name.setText(response.getString("Name"));
                mobile.setText(response.getString("Mobile"));
            } catch (JSONException e) {
                e.printStackTrace();
            }
        }
    }, new Response.ErrorListener() {
               @Override
               public void onErrorResponse(VolleyError error) {
                   error.printStackTrace();
               }
    }){
       @Override
       public Map<String, String> getHeaders() throws AuthFailureError{
            HashMap<String, String> headers = new HashMap<String, String>();
            headers.put("Content-Type", "application/json; charset=utf-8");
            return headers;
       }
};

MySingleton.getInstance(getApplicationContext()).addToRequestQueue(jsonObjectRequest);

Answer 1

尝试使用volley StringRequest ，似乎服务器正在向您发送字符串而不是JsonOBJECTS。如果您需要JsonObject，则必须在服务器端进行一些更改。如果没有试试这个：

RequestQueue queue = Volley.newRequestQueue(getApplicationContext());
        StringRequest request = new StringRequest(Request.Method.POST,
                Addresses.LOGIN_URL, new Response.Listener<String>() {
            @Override
            public void onResponse(String response) {
                try {
                    JSONObject jsonObject = new JSONObject(response);
                    Log.d("Response", jsonObject .toString());
                    name.setText(jsonObject .getString("Name"));
                    mobile.setText(jsonObject .getString("Mobile"));
                } catch (JSONException e) {
                    e.printStackTrace();
                }
            }
        }, new Response.ErrorListener() {
            @Override
            public void onErrorResponse(VolleyError error) {
                error.printStackTrace();
            }
        }){
            @Override
            public Map<String, String> getHeaders() throws AuthFailureError {
                HashMap<String, String> headers = new HashMap<String, String>();
                headers.put("Content-Type", "application/json; charset=utf-8");
                return headers;
            }
        };

queue.add(request);

Answer 2

如果您的服务器以json格式接收值，这可能是您的解决方案。

JSONObject jsonobject= new JSONObject();
jsonobject.put("email",email.getText().toString());



    JsonObjectRequest jsonObjectRequest=new JsonObjectRequest(Request.Method.POST, json_url, jsonobject, new Response.Listener<JSONObject>() {
                    @Override
                    public void onResponse(JSONObject response) {
                        try {
                            Log.d("Response", response.toString());
                            name.setText(response.getString("Name"));
                            mobile.setText(response.getString("Mobile"));
                        } catch (JSONException e) {
                            e.printStackTrace();
                        }
                    }
                }, new Response.ErrorListener() {
                    @Override
                    public void onErrorResponse(VolleyError error) {
                        error.printStackTrace();
                    }
                }){
                    @Override
                    public Map<String, String> getHeaders() throws AuthFailureError {
                        HashMap<String, String> headers = new HashMap<String, String>();
                        headers.put("Content-Type", "application/json; charset=utf-8");
                        return headers;
                    }
                };
                MySingleton.getInstance(getApplicationContext()).addToRequestQueue(jsonObjectRequest);

如何在Volley中使用JSONObjectRequest发送数据并且我得到错误值<br of =“”type =“”java.lang.string =“”can =“”be =“”converted =“”to =“ “jsonobject

2 个答案: