我可以在JavaFX GUI中包含JavaFX LineChart吗?

时间:2017-01-24 00:33:14

标签: java javafx linechart scene gridpane

我想声明两个面板的JavaFX GridPane,左面板包含一个按钮。单击按钮时,右侧面板中将显示LineChart。编码可能看起来像这样:

public class FormLineChart extends Application {

    @Override 
    public void start(Stage stage) {
        stage.setTitle("A Title");
        //Create the grid for defining the GUI
        GridPane grid = new GridPane();
        // add gui objects to grid
        ...
        //Create the chart
        final LineChart<Number, Number> lineChart = new LineChart<>(xAxis, yAxis);
        ...
        // Create the series and display the lineChart
        lineChart.getData().add(series);
        stage.setScene(scene);

        Scene scene = new Scene(grid, 427, 319);
        //How do we add 'lineChart' to scene as well as keeping 'grid'?
        stage.setScene(scene);
        stage.show();
    }

    public static void main(String[] args) {
        launch(args);
    }
}

特别是可以组合网格&#39;和&#39; lineChart&#39;在一个场景?目前只显示GUI,因为on强制将场景设置为网格。

1 个答案:

答案 0 :(得分:0)

正如@James_D所说,你只需要另一个容器即可实现。 Pane可以包含GUI控件以及另一个Pane

在下面的示例中,我在GridPane内放置了一个带有几个按钮的BorderPane,将窗口划分为左右两部分。

@Override
public void start(Stage stage) {
    stage.setTitle("A Title");

    // Root element
    BorderPane root = new BorderPane();

    // GridPane
    GridPane grid = new GridPane();
    grid.setPadding(new Insets(10,10,10,10));
    grid.setVgap(10);
    grid.add(new Button("Button 1"), 0, 0);
    grid.add(new Button("Button 2"), 0, 1);
    grid.add(new Button("Button 3"), 0, 2);

    // Chart
    final NumberAxis xAxis = new NumberAxis();
    final NumberAxis yAxis = new NumberAxis();
    final LineChart<Number, Number> lineChart = new LineChart<>(xAxis, yAxis);
    XYChart.Series series = new XYChart.Series();
    series.setName("Chart");
    series.getData().add(new XYChart.Data(1, 5));
    series.getData().add(new XYChart.Data(2, 10));
    lineChart.getData().add(series);

    root.setLeft(grid);
    root.setRight(lineChart);

    Scene scene = new Scene(root, 600, 300);

    stage.setScene(scene);
    stage.show();
}