实际上我没有这样运行。也许我误解了一些事情,无论如何这是不可能的。我试图在同一个队列上配置2个侦听器,相同的交换但只有路由键应该不同。我的问题是不知何故事情搞砸了。结果是监听器A获取了用于监听器B的消息。但有时只有一切,有时一切正常。有什么建议吗?
的myconfig
@Bean
public ConnectionFactory connectionFactory() {
CachingConnectionFactory connectionFactory = new CachingConnectionFactory(getHostname());
connectionFactory.setUsername(getUsername());
connectionFactory.setPassword(getPassword());
return connectionFactory;
}
@Bean
public RabbitAdmin rabbitAdmin() {
return new RabbitAdmin(connectionFactory());
}
@Bean
public SimpleRabbitListenerContainerFactory rabbitListenerContainerFactory() {
SimpleRabbitListenerContainerFactory factory = new SimpleRabbitListenerContainerFactory();
factory.setMessageConverter(new CustomMessageConverter());
factory.setConnectionFactory(connectionFactory());
factory.setAcknowledgeMode(AcknowledgeMode.AUTO);
factory.setConcurrentConsumers(10);
factory.setMaxConcurrentConsumers(10);
return factory;
}
@Override
public void configureRabbitListeners(RabbitListenerEndpointRegistrar registrar) {
registrar.setMessageHandlerMethodFactory(myHandlerMethodFactory());
}
@Bean
public DefaultMessageHandlerMethodFactory myHandlerMethodFactory() {
DefaultMessageHandlerMethodFactory factory = new DefaultMessageHandlerMethodFactory();
factory.setMessageConverter(new MappingJackson2MessageConverter());
return factory;
}
MyListeners A
@RabbitListener(bindings = @QueueBinding(value = @Queue(value = QUEUE, durable = "true"), exchange = @Exchange(value = EXCHANGE, type = "topic", durable = "true", ignoreDeclarationExceptions = "true"), key = "routingKeyA"))
public String myListenerA(@Payload PayloadA payload, @Header(AmqpHeaders.CORRELATION_ID) byte[] correlationId) {
return SUCCESS_RESPONSE;
}
MyListener B
@RabbitListener(bindings = @QueueBinding(value = @Queue(value = QUEUE, durable = "true"), exchange = @Exchange(value = EXCHANGE, type = "topic", durable = "true", ignoreDeclarationExceptions = "true"), key = "routingKeyB"))
public String myListenerB(@Payload PayloadB payload, @Header(AmqpHeaders.CORRELATION_ID) byte[] correlationId) {
return SUCCESS_RESPONSE;
}
其他信息:此队列中有20位消费者。 Thx提前!
答案 0 :(得分:1)
RabbitMQ不会这样做;与JMS不同,无法从队列中选择消息(例如,基于路由密钥)。
您所做的就是使用2个不同的路由键将相同的队列绑定到交换机。所以,是的,任何一个监听器都会收到消息,无论它是如何进入队列的。
使用RabbitMQ,每个侦听器都需要一个单独的队列。当生产者发布到交换机时,代理将根据他使用的路由密钥将消息路由到正确的队列。
如果每个侦听器都有多个实例,则将相应地分发消息(每个队列只传递一个)。