Question

我有一个查询，我没有直观地看到语法或格式错误。

但执行时，SSMS报告“值”附近存在语法错误。

select * from sw.Users u 
join sw.Locations l 
join sw.Organizations o 
on u.LocationID = l.LocationID 
and l.OrganizationID = o.OrganizationID 
and o.OrganizationName = 'Value'

错误

Msg 102，Level 15，State 1，Line 38'Value'附近的语法不正确。

尝试以下结果：

select * from sw.Users u 
join sw.Locations l 
on u.LocationID = l.LocationID

为什么第一个连接查询报告错误？

Answer 1

您的第一次加入错过了加入条件。 syntax为：a JOIN b ON ...，而不仅仅是a JOIN b。

如果您要加入三个表，则需要分两步完成，

(a JOIN b ON ...) JOIN c ON ...

或

a JOIN (b JOIN c ON ...) ON ...

请注意，括号是可选的，这可能是错误消息显示“near Value”的原因 - SQL Server假定您要使用第二种语法并错过了结尾处的第二个ON言。

第一种语法通常更容易阅读。就个人而言，我会按如下方式编写SQL语句：

SELECT * 
  FROM sw.Users AS u 
       INNER JOIN sw.Locations AS l ON u.LocationID = l.LocationID 
       INNER JOIN sw.Organizations AS o ON l.OrganizationID = o.OrganizationID 
 WHERE o.OrganizationName = 'Value'

每个JOIN行添加另一个表，其ON子句描述旧结果集和新表之间的关系。实际的过滤条件在WHERE子句中。

Answer 2

您需要在每次加入后添加“on”。

select * from sw.Users u 
join sw.Locations l 
on u.LocationID = l.LocationID 
join sw.Organizations o 
on l.OrganizationID = o.OrganizationID 
where o.OrganizationName = 'Value'

有关详细信息，请查看here。

Answer 3

每次（ON）INNER

后，您需要使用JOIN个关键字

SELECT  *
FROM    sw.Users            u
JOIN    sw.Locations        l   ON u.LocationID = l.LocationID 
JOIN    sw.Organizations    o   ON l.OrganizationID = o.OrganizationID
                                   AND o.OrganizationName = 'Value'

Answer 4

尝试像这样重组

select * from sw.Users u 
join sw.Locations l    on u.LocationID = l.LocationID 
join sw.Organizations o on
l.OrganizationID = o.OrganizationID 
and o.OrganizationName = 'Value'

MSSQL JOIN查询 - '值'附近的语法不正确

4 个答案: