将oracle对象类型传递给j​​ava存储过程

时间:2017-01-23 18:14:14

标签: java oracle stored-procedures oracle11g

是否可以将oracle对象类型传递给j​​ava存储过程。这就是我到目前为止所拥有的。

Java存储过程:

create or replace and compile java source named Example as
import java.sql.SQLData;
import java.sql.SQLException;
import java.sql.SQLInput;
import java.sql.SQLOutput;

public class Example {

    public static void test(ExObj obj) {
        System.out.println(obj.client);
    }

    public static class ExObj implements SQLData {

        public String client = "";

        public String sql_type = "EXAMPLE_OBJECT";

        public ExObj(String client, String sql_type) {
            this.client = client;

            this.sql_type = sql_type;
        }

        /* IMPLEMENTS SQLData */

        public void setSqlType(String sqlType) {
            sql_type = sqlType;
        }

        public void writeSQL(SQLOutput stream) throws SQLException {
            stream.writeString(this.client);
        }

        public String getSQLTypeName() {
            return sql_type;
        }

        public void readSQL(SQLInput stream, String sqlTypeName) throws SQLException {
            sql_type = sqlTypeName;

            this.client = stream.readString();
        }

    }
}

Oracle程序:

CREATE OR REPLACE PROCEDURE example(ex_obj in example_object)
AS LANGUAGE JAVA
NAME 'Example.test(java.sql.Struct)';

Oracle对象类型:

create or replace type example_object as object(
  client varchar2(40)
)

调用程序的脚本:

declare
  l_output DBMS_OUTPUT.chararr;
  l_lines  INTEGER := 1000;

  l_obj example_object;
begin
  DBMS_OUTPUT.enable(1000000);
  DBMS_JAVA.set_output(1000000);

  l_obj := example_object('client');
  example(l_obj);

  DBMS_OUTPUT.get_lines(l_output, l_lines);

  FOR i IN 1 .. l_lines LOOP
    -- Do something with the line.
    -- Data in the collection - l_output(i)
    DBMS_OUTPUT.put_line(l_output(i));
  END LOOP;
end;

运行脚本时我得到:

  

ORA-29531:类示例中没有方法测试

     

ORA-06512:在"示例",第1行

     

ORA-06512:第17行

我认为它是因为oracle object_type没有正确映射到java类。有没有办法做到这一点,如果是这样,我做错了什么?

1 个答案:

答案 0 :(得分:1)

下面提到的代码问题可能是原因。

1)您必须声明type object的{​​{1}}变量,以便您可以使用它。您无法直接将object用作datatype。见下文:

演示:

create or replace type example_object as object(
  client varchar2(40)
  );

 /

--Created a type of the object
create or replace type x is table of example_object;

/


 CREATE OR REPLACE PROCEDURE example(ex_obj in X)
    AS
  begin

    DBMS_OUTPUT.put_line('Example.test(java.sql.Struct');
    DBMS_OUTPUT.put_line('Inside the Procedure');
    DBMS_OUTPUT.put_line (ex_obj(1).client);

    end;
  /

    DECLARE
       l_output   DBMS_OUTPUT.chararr;
       l_lines    INTEGER := 1000;

       l_obj      x := x();      

    BEGIN
       DBMS_OUTPUT.enable (1000000);
       --DBMS_JAVA.set_output (1000000);

       --You need to mention the position where the record will be saved in table.
       l_obj.extend(); 
       l_obj(1) := example_object('client1');

       example (l_obj);

       DBMS_OUTPUT.put_line (l_obj(1).client);

       DBMS_OUTPUT.get_lines (l_output, l_lines);

       FOR i IN 1 .. l_lines
       LOOP
          -- Do something with the line.
          -- Data in the collection - l_output(i)
          DBMS_OUTPUT.put_line (l_output (i));
       END LOOP;
    END;

/