Question

我有一个页面，我将来自mysql的数据调用到一个表中。我正在尝试创建一种情况，他们可以点击桌面上的日期，并将它们链接到另一个页面。这是我正在处理的代码

$q = "SELECT*FROM forum";
$r = mysqli_query($dbc,$q);
if (mysqli_num_rows($r)>0)
{
    echo'<table><tr><th>Posted By</th>
    <th>Subject</th><th id="msg">Message</th></tr>';
    while ($row=mysqli_fetch_array($r,MYSQLI_ASSOC))
    {
        echo'<tr>
        <td>'.$row['first_name'].''.$row['last_name'].'<br>
                                    '.$row['post_date'].'</td>
        <td>'.$row['subject'].'</td><td>'.$row['message'].'</td>
        </tr>';
    }
    echo '</table>';
}
else
{echo '<p>There are currently no messages.</p>';}

我正在尝试将锚标签放在此代码上

 '.$row['post_date'].'

我试过这个

 <a href="edit.php">'.$row['post_date'].'</a>

但它无效

Answer 1

试试这个：

<a href="edit.php"><?= $row['post_date']; ?></a>

或更短的变体：

SELECT 
        ID,
         CASE WHEN ID = 1 Then 'Open' 
              WHEN Id = 2 then 'Close'
              When ID = 3 then 'Transfer' 
              else '' END AS ActionType,Sum(Quantity) as Quantity,sum(Fee)
 FROM Table_Name
Group by
ID,
CASE WHEN ID = 1 Then 'Open' 
              WHEN Id = 2 then 'Close'
              When ID = 3 then 'Transfer' 
              else '' END

如何在锚标记中调用php变量

1 个答案: