我试图从数据集中翻转键值来进行排序。但是,map函数返回无效的语法错误
rdd = clean_headers_rdd.rdd\
.filter(lambda x: x['date'].year == 2016)\
.map(lambda x: (x['user_id'], 1)).reduceByKey(lambda x, y: x + y)\
.map(lambda (x, y): (y, x)).sortByKey(ascending = False)
答案 0 :(得分:1)
PEP 3113 -- Removal of Tuple Parameter Unpacking
the transition plan推荐的方法:
rdd.map(lambda x_y: (x_y[1], x_y[0])
operator
模块的快捷方式:
from operator import itemgetter
rdd.map(itemgetter(1, 0))
切片:
rdd.map(lambda x: x[::-1])