运行此查询而不更改sql_mode

时间:2017-01-23 07:56:20

标签: mysql sql group-by sql-mode

我正在尝试在测试环境中测试查询,如下所示

查询: -

 SELECT a.aggreatorid AS aggreatorid, '' AS txndesc, DATE_FORMAT(DATE(b.txndate),'%d/%m/%Y') AS txndate,
  SUM(txncredit) AS txncredit, SUM(txndebit) AS txndebit  
  FROM  walletmast a INNER JOIN wallettransaction b ON a.walletid=b.walletid  
  AND txndate  BETWEEN CURDATE() - INTERVAL 3 DAY AND CURDATE()  
  GROUP BY a.aggreatorid, DATE(b.txndate)
  ORDER BY txndate DESC

查询正在抛出

错误: -

SQL Error (1055): 'digitalpurse.b.txnDate' isn't in GROUP BY

查询在我的本地环境中工作,但在大量搜索后没有在测试环境中查找我发现测试环境有 sql_modes ,无法根据应用程序流程和安全目的进行更改

SQL模式: -

 @@sql_mode                                                                                                                                |
+------------------------------------------------------------+
| ONLY_FULL_GROUP_BY,
STRICT_TRANS_TABLES,
NO_ZERO_IN_DATE,
NO_ZERO_DATE,
ERROR_FOR_DIVISION_BY_ZERO,
NO_AUTO_CREATE_USER,
NO_ENGINE_SUBSTITUTION |

有没有办法在不更改sql_mode的情况下运行此查询? 如果需要任何其他信息,请与我们联系。提前谢谢你:D

2 个答案:

答案 0 :(得分:1)

将查询移动到选择DATE(b.txndate)的子查询中,使其与GROUP BY子句匹配,然后在主查询中执行格式化。

SELECT aggreatorid, '' AS txndesc, DATE_FORMAT(txndate, '%d/%m/%Y') AS txndate,
    txncredit, txndebt
FROM (
    SELECT a.aggreatorid AS aggreatorid, DATE(b.txndate) AS txndate,
        SUM(txncredit) AS txncredit, SUM(txndebit) AS txndebit  
    FROM  walletmast a 
    INNER JOIN wallettransaction b ON a.walletid=b.walletid  
    WHERE txndate BETWEEN CURDATE() - INTERVAL 3 DAY AND CURDATE()  
    GROUP BY a.aggreatorid, DATE(b.txndate)
) AS x
ORDER BY txndate DESC

答案 1 :(得分:1)

SELECT a.aggreatorid
     , '' txndesc
     , DATE_FORMAT(DATE(b.txndate),'%d/%m/%Y') dt
     , SUM(txncredit) txncredit
     , SUM(txndebit) txndebit  
  FROM  walletmast a 
  JOIN wallettransaction b 
    ON a.walletid=b.walletid  
  AND txndate  BETWEEN CURDATE() - INTERVAL 3 DAY AND CURDATE()  
   GROUP BY a.aggreatorid, dt, txndesc
   ORDER BY txndate DESC

就个人而言,我认为最好的日期出现在最终用户区域设置中,所以练习JavaScript或PHP而不是MySQL