Question

我有一个django Listview，我正在使用django-el-pagination＆ajax ajax无尽的分页来分页我的结果，它运作良好。问题是我需要对它应用一些过滤器，并且不知道如何做到这一点。

我可以通过GET将参数发送到视图吗？已经搜索了很多，似乎以前没有人遇到过这个问题。

Answer 1

始终在get_queryset()函数中返回数据。

如果您只想从数据库中过滤，只需返回对象即可。

class IndexView(AjaxListView):
    template_name = '****'
    context_object_name = '****'
    page_template = '****'

    def get_queryset(self):
        return your_model.objects.filter(title='***').order_by('**')

否则，如果您想从非数据库获取数据，则需要根据this answer实现代理。

如果没有，分页ajax将请求所有数据，然后将其切片。代理会在查询时切换数据。

这是我从ElasticSearch获取数据的过滤器。

class IndexView(AjaxListView):
    template_name = '****'
    context_object_name = '****'
    page_template = '****'

        def get_queryset(self):
    params = {}
    # get query params
        for item in self.request.GET.items():
            if item[0] == 'page' or item[0] == 'querystring_key':
                continue
            params[item[0]] = item[1]

        # no filter
        if len(params) == 0:
            return ****.objects.filter().order_by('-date')

        else:
            return ESResult(params)

class ESResult(object):

    def __init__(self, params):
        self.params = params

    def __len__(self):
        s = self.search_es()
        if s:
            s = s[:1]
            r = s.execute()
            return r['hits']['total']
        else:
            return 0

    def __getitem__(self, item):
        assert isinstance(item, slice)
        result = []
        s = self.search_es()

        if s:
            s = s[item.start:item.stop]   # slice before querying
            r = s.execute()

            for a in r.to_dict()['hits']['hits']:
                one = a['_source']
                one['id'] = int(a['_id'])
                result.append(one)

        return result

    def search_es():
        ...
        # filter request here
        ...

Answer 2

AjaxListView使用的列表对象由get_queryset()方法定义。要根据用户输入过滤查询集，可以参考POST方法：

from app.forms import BlogFilterForm

class Blog(LoginRequiredMixin, AjaxListView):
    context_object_name = "posts"
    template_name = 'blog/blog.html'
    page_template = 'blog/post_list.html'
    success_url = '/blog'

    def get_queryset(self): # define queryset
        queryset = Post.objects.all() # default queryset
        if self.request.method == 'POST': # check if the request method is POST
            form = BlogFilterForm(self.request.POST) # define form
            if form.is_valid(): 
                name = form.cleaned_data['name'] # retrieve data from the form
                if name:
                    queryset = queryset.filter(name=name) # filter queryset
        else:
            queryset = queryset
        return queryset 

    def get_context_data(self, **kwargs):
        context = super(Blog, self).get_context_data(**kwargs)
        context['form'] = BlogFilterForm() # define context to render the form on GET method
        return context

    def post(self, request, *args, **kwargs): # define post method
        return super(Blog, self).get(request, args, kwargs)

无尽的分页应该可以正常工作。 using filters with django-endless-pagination

如何使用django-el-pagination进行过滤？

2 个答案: