Question

我设法使用CSS更改了Button（在本例中为切换按钮）的背景，但我无法弄清楚如何让按下的按钮保持其颜色。

现在按钮的颜色为蓝色，如果单击并按住按钮，按钮将变为绿色。

但我需要保持按钮的颜色为绿色，直到我再次按下按钮再次变为蓝色。

以下是代码：

#include <gtk/gtk.h>

void myStyleCss(void);
void createWind(GtkWidget **window, gint width, gint height);
void createGrid(GtkWidget **grid, GtkWidget **window, const gchar *name);

void chngBkgrd(gpointer *data);

int main(int argc, char *argv[]){
    GtkWidget *window;
    GtkWidget *grid;
    GtkWidget *button;

    gtk_init(&argc, &argv);
    myStyleCss();
    createWind(&window, 350, 250);
    createGrid(&grid, &window, "myGrid");

    button = gtk_toggle_button_new_with_label("tgl_btn");
    g_signal_connect (button, "toggled", G_CALLBACK(chngBkgrd),(gpointer *)button);
    gtk_grid_attach (GTK_GRID (grid), button, 0 , 0, 1, 1);


    gtk_widget_show_all(window);
    gtk_main();
}

void myStyleCss(void){
    GtkCssProvider *provider;
    GdkDisplay *display;
    GdkScreen *screen;

    provider = gtk_css_provider_new ();
    display = gdk_display_get_default ();
    screen = gdk_display_get_default_screen (display);
    gtk_style_context_add_provider_for_screen (screen,
                                               GTK_STYLE_PROVIDER(provider),
                                               GTK_STYLE_PROVIDER_PRIORITY_APPLICATION);

    const gchar *myCssFile = "mystyle.css";
    GError *error = 0;

    gtk_css_provider_load_from_file(provider,
                                    g_file_new_for_path(myCssFile), &error);
                                    g_object_unref (provider);
}

void createWind(GtkWidget **window, gint width, gint height){
    *window = gtk_window_new(GTK_WINDOW_TOPLEVEL);
    gtk_window_set_title(GTK_WINDOW(*window), "MyApp");
    gtk_window_set_default_size(GTK_WINDOW(*window), width, height);
    gtk_window_set_resizable (GTK_WINDOW(*window), TRUE);
    gtk_container_set_border_width(GTK_CONTAINER(*window), 5);
    g_signal_connect(*window, "destroy", G_CALLBACK(gtk_main_quit), NULL);
}

void createGrid(GtkWidget **grid, GtkWidget **window, const gchar *name){
    *grid = gtk_grid_new ();
    gtk_grid_set_row_homogeneous(GTK_GRID(*grid), TRUE);
    gtk_grid_set_column_homogeneous(GTK_GRID(*grid), TRUE);
    gtk_widget_set_name(*grid, name);
    gtk_container_set_border_width(GTK_CONTAINER (*grid), 50);
    g_object_set (*grid, "margin", 0, NULL);
    gtk_container_add (GTK_CONTAINER (*window), *grid);
}

void chngBkgrd(gpointer *data){
    if (gtk_toggle_button_get_active(GTK_TOGGLE_BUTTON(data))){
        g_print("On\n");
    }else{
        g_print("Off\n");
    }
}

这是CSS文件（mystyle.css）：

GtkWindow {
    background-color: #A4A4A4;
    color: cyan;
    border-width: 3px;
    border-color: blue;
}

#myGrid {
    background-color: white;
    border-style: solid;
    border-width: 3px;
    border-radius: 15px;
    border-color: grey;
}

#myChild {
    background-color: red;
    border-style: solid;
    border-width: 3px;
    border-radius: 15px;
    border-color: grey;
}

#tgl_btn{
    background-color: red;
    color: red;
}


GtkButton {
    background-image: none;
    background-color: blue;
}

GtkButton:active {
    background-color: #00FF00;
}

我该怎么做？

Answer 1

在我读完以下内容之后，我设法弄明白了怎么做

：active - 直到GTK 3.16才被使用;相当于：按下的类在按下时使用＆＃34;

解决方案是使用：已检查：

GtkButton:checked{
    background-color: #00FF00;
}

在GTK3中按下时更改Togle按钮的背景颜色（C语言）

1 个答案: