Question

我想使用Regex获取此String的所有.mp4网址。

另外，我想知道如何使用Regex只获取最后一个.mp4网址。

谢谢

contentType=application/x-mpegURL, url=https://video.twimg.com/amplify_video/822938952332144642/pl/BjHU8aBCbOgZNzXQ.m3u8}, 

Variant{bitrate=0, contentType=application/dash+xml, url=https://video.twimg.com/amplify_video/822938952332144642/pl/BjHU8aBCbOgZNzXQ.mpd}, 

Variant{bitrate=320000, contentType=video/mp4, url=https://video.twimg.com/amplify_video/822938952332144642/vid/320x180/YqZ72rzLj3VWVhy4.mp4}, 

Variant{bitrate=832000, contentType=video/mp4, url=https://video.twimg.com/amplify_video/822938952332144642/vid/640x360/A2vMgzo2ElpPP6TE.mp4}, 

Variant{bitrate=2176000, contentType=video/mp4, url=https://video.twimg.com/amplify_video/822938952332144642/vid/1280x720/j9xbNzRZqEbYs_2s.mp4}]}]";

Answer 1

<强>正则表达式：

$(document).on('keydown', 'input', function(e) {
    // keycode first
    if (e.keyCode==40 || e.keyCode==13) {
    }

    // keycode second etc.
    if (e.keyCode==39) {
    }

    if (e.keyCode==38) {
    }

    if (e.keyCode==37) {
    }
});

文字https?.*?\.mp4

随后是可选的＆＃39;：http

如果他们都使用HTTPS，请删除问号。

跟随尽可能少的字符：s?

后跟mp4扩展名（字面点）.*?

Answer 2

2方法：

如果您确定网址始终以https://开头，并且在完整网址完成后不会包含mp4，那么您可以使用 pattern = "https://.*mp4";

String[] arr = {
    "contentType=application/x-mpegURL, url=https://video.twimg.com/amplify_video/822938952332144642/pl/BjHU8aBCbOgZNzXQ.m3u8}",

    "Variant{bitrate=0, contentType=application/dash+xml, url=https://video.twimg.com/amplify_video/822938952332144642/pl/BjHU8aBCbOgZNzXQ.mpd}",

    "Variant{bitrate=320000, contentType=video/mp4, url=https://video.twimg.com/amplify_video/822938952332144642/vid/320x180/YqZ72rzLj3VWVhy4.mp4}",

    "Variant{bitrate=832000, contentType=video/mp4, url=https://video.twimg.com/amplify_video/822938952332144642/vid/640x360/A2vMgzo2ElpPP6TE.mp4}",

    "Variant{bitrate=2176000, contentType=video/mp4, url=https://video.twimg.com/amplify_video/822938952332144642/vid/1280x720/j9xbNzRZqEbYs_2s.mp4}]}]" 
};
String pattern = "https://.*mp4";
Pattern r = Pattern.compile(pattern);

for (String line : arr) {
    Matcher m = r.matcher(line);
    if (m.find()) {
        System.out.println(m.group(0));
    } else {
        System.out.println("NO MATCH");
    }
}

如果没有，支持所有类型的网址，然后稍加修改，将模式更改为定义here，

String pattern = 
    "(((ht|f)tp(s?)\\:\\/\\/|~\\/|\\/)|www.)" + 
    "(\\w+:\\w+@)?(([-\\w]+\\.)+(com|org|net|gov" + 
    "|mil|biz|info|mobi|name|aero|jobs|museum" + 
    "|travel|[a-z]{2}))(:[\\d]{1,5})?" + 
    "(((\\/([-\\w~!$+|.,=]|%[a-f\\d]{2})+)+|\\/)+|\\?|#)?" + 
    "((\\?([-\\w~!$+|.,*:]|%[a-f\\d{2}])+=?" + 
    "([-\\w~!$+|.,*:=]|%[a-f\\d]{2})*)" + 
    "(&(?:[-\\w~!$+|.,*:]|%[a-f\\d{2}])+=?" + 
    "([-\\w~!$+|.,*:=]|%[a-f\\d]{2})*)*)*" + 
    "(#([-\\w~!$+|.,*:=]|%[a-f\\d]{2})*)?\\b"+"mp4";

输出：

NO MATCH
NO MATCH
https://video.twimg.com/amplify_video/822938952332144642/vid/320x180/YqZ72rzLj3VWVhy4.mp4
https://video.twimg.com/amplify_video/822938952332144642/vid/640x360/A2vMgzo2ElpPP6TE.mp4
https://video.twimg.com/amplify_video/822938952332144642/vid/1280x720/j9xbNzRZqEbYs_2s.mp4

用于在字符串中查找mp4的正则表达式

2 个答案: