这似乎应该是微不足道的,但结果是出乎意料的
# create empty list
list=c()
# create vector of one hundred 4s
fours=rep(4,100)
# for loop. Try to split into 10
for(i in seq(10)){
# split into chunks: i=1, take fours[1:10]; i=2, fours[11:20]...
# when i=10, should return fours[91:100]
chunks=fours[1+10*(i-1):10*i]
# add smaller lists of four back into bigger list
list=c(list,chunks)
}
list
# returns [1] 4 4 4 4 4 4 4 4 4 4 NA 4 4 4 4 NA NA NA NA NA NA 4 4 NA NA
[26] NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA
我希望能够获得一百4
个值。
答案 0 :(得分:0)
需要更正以下行(为正确的算术运算添加括号):
chunks=fours[1+10*(i-1):10*i]
更正后的代码:
fours=rep(4,100)
chunks = list()
for(i in 1:10){
chunks[[i]] = fours[(1+((i-1)*10)) : (10+((i-1)*10))]
}
chunks
或者:
fours=rep(4,100)
chunks = list()
for(i in 1:10){
start = 1+((i-1)*10)
chunks[[i]] = fours[ start : (9+start)]
}
chunks
输出:
[[1]]
[1] 4 4 4 4 4 4 4 4 4 4
[[2]]
[1] 4 4 4 4 4 4 4 4 4 4
[[3]]
[1] 4 4 4 4 4 4 4 4 4 4
[[4]]
[1] 4 4 4 4 4 4 4 4 4 4
[[5]]
[1] 4 4 4 4 4 4 4 4 4 4
[[6]]
[1] 4 4 4 4 4 4 4 4 4 4
[[7]]
[1] 4 4 4 4 4 4 4 4 4 4
[[8]]
[1] 4 4 4 4 4 4 4 4 4 4
[[9]]
[1] 4 4 4 4 4 4 4 4 4 4
[[10]]
[1] 4 4 4 4 4 4 4 4 4 4