Question

理想情况下，在我的数据库表中，我有用户名，姓名，位置，电子邮件。

现在我在 view.php 中有一个表，它从数据库中返回值。

表标题包含名称，用户名和更多信息，其中名称和 用户名 < / strong>直接来自数据库，而 更多信息 每行都有一个按钮。单击该按钮时，它应该弹出显示位置和电子邮件。

问题：如果具体点击按钮，如何检索用户的位置和电子邮件？

示例：

user1，joe doe，[button] - ＆gt; user1位置，user1 @ email.com

user2，jay doe，[button] - ＆gt; user2位置，user2 @ email.com

代码： p.s。代码包括分页。

Controller.php这样

function pagination() { $config = array(); $config['base_url'] = base_url() . "controller/pagination"; $total_row = $this->model->record_count(); $config["total_rows"] = $total_row; $config["per_page"] = 8; $config['uri_segment'] = 3; /* $config['use_page_numbers'] = TRUE; */ $config['num_links'] = $total_row; $config['cur_tag_open'] = ' <a class="current">'; $config['cur_tag_close'] = '</a>'; $config['next_link'] = '<span aria-hidden="true">»</span>'; $config['prev_link'] = '<span aria-hidden="true">«</span>'; $this->pagination->initialize($config); $page = ($this->uri->segment(3)) ? $this->uri->segment(3) : 0; $data["results"] = $this->model->fetch_data($config["per_page"], $page); $str_links = $this->pagination->create_links(); $data["links"] = explode(' ', $str_links); // View data according to array. $this->load->view("view-employees", $data); }

model.php

public function record_count() { return $this->db->count_all('users'); } public function fetch_data($limit, $start) { $this->db->limit($limit, $start); $query = $this->db->get('users'); if ($query->num_rows() > 0) { foreach ($query->result() as $row) { $data[] = $row; } return $data; } return false; }

view.php

<tr> <th>username</th> <th>name</th> <th>more</th> </tr> <tr> <?php foreach ($results as $data) { ?> <td><?php echo $data->username; ?></td> <td><?php echo $data->name; ?></td> <td> <button type='button' class='btn'> <?php echo $data->location; echo $data->email; ?> </button> </td> </tr>

Answer 1

您可以编写一个Codeigniter控制器，它将返回电子邮件和位置
然后编写Javascript函数，调用此控制器以检索数据asJSON-Data

这两个，编写一个返回JSON的控制器和一个如何从JS调用这个控制器的例子可以在这里找到：

Code Igniter - How to return Json response from controller

Answer 2

试试这样..

MODEL：

<tr>
    <th>username</th>
    <th>name</th>
    <th>more</th>
</tr>
<tr>
    <?php foreach ($results as $data) { ?>
    <td><?php echo $data['username']; ?></td>
    <td><?php echo $data['name']; ?></td>
    <td>
        <button type='button' class='btn'>
           <?php echo $data['location']; 
                 echo $data['email'];
           ?>
        </button>
    </td>
<?php } ?>
</tr>

查看：

enter code here

#!/usr/bin/python

import paramiko
import sys
import time
import Tkinter
import time, os, threading
from Tkinter import *
a=Tkinter.Tk()



#A function that logins and execute commands
def fn():
    HOST=raw_input('Enter HOST IP: ')

    USER=raw_input('Enter USER NAME: ')

    PASS=raw_input('Enter PASSWORD: ')

    client1=paramiko.SSHClient()
    client1.set_missing_host_key_policy(paramiko.AutoAddPolicy())
    client1.connect(HOST,username=USER,password=PASS)
    print "SSH connection to %s established" %HOST
    com="cat /etc/motd"
    print "Welcome to Account",
    com1=raw_input("Enter the command:")
    com2=raw_input("Enter if you you want to run multiple command:")
    #Gather commands and read the output from stdout
    stdin, stdout, stderr = client1.exec_command(com)
    print stdout.read()
    stdin, stdout, stderr = client1.exec_command( com1)
    print stdout.read()
    stdin, stdout, stderr = client1.exec_command( com2 )
    print stdout.read()
    client1.close()
    top = os.system("sudo su -")
    s = str(top)
    print "Logged out of device %s" %HOST



b = Button(a, text='Welcome to the Login World', command=fn)
b.pack()
b.mainloop()

Codeigniter：使用按钮单击查看数据库

2 个答案: