我有以下问题,我正在使用Codeigniter,我在我的控制器的索引中做了一个小验证,这是代码:
function index()
{
$user = $this->session->userdata("id");
$data = $this->customer_model->get_rol_user($user);
foreach ($data as $row) {
if ($row->Url === 'customer/index'){
$this->load->view('guest/head');
$this->load->view('guest/nav');
$this->load->view('guest/section');
$this->load->view('customer/customer_view');
}
}
redirect(base_url());
}
查询工作正常,我已经检查过,它返回我需要的内容如下:
如果在我的查询结果中,我有与我的条件相同的值,如果在这种情况下,如果是,我将不得不加载视图,否则我重定向到我的应用程序的主页,我在foreach中失败了?
这是我的模特:
function get_rol_user($user){
$query = $this->db-> query("SELECT p.Url
FROM User AS u INNER JOIN rol AS r ON u.fk_rol = r.id_rol
INNER JOIN rol_page AS n ON n.fk_rol = r.id_rol
INNER JOIN page AS p ON n.fk_page = p.id_page
WHERE u.id_user ='".$user."'");
if ($query->num_rows() > 0) {
return $query->result();
}
}
答案 0 :(得分:0)
喜欢这个..
data = json.loads(request.data)
user = data['user']
答案 1 :(得分:0)
仅在设置了标志时添加标志并重定向(在我的示例中,它设置为false
):
$load_view = false;
foreach ($data as $row) {
if ($row->Url === 'customer/index'){
// flag tells us that `if` is executed
$load_view = true;
$this->load->view('guest/head');
$this->load->view('guest/nav');
$this->load->view('guest/section');
$this->load->view('customer/customer_view');
}
}
// no Url is found - do a redirect.
if (!$load_view) {
redirect(base_url());
}