我如何修复此错误,其中我收到“无效的方法声明;需要返回类型”和错误“缺少方法体或声明抽象”
请帮忙。我很感激善良。
private void login(final String email, final String password) {
//Tag used to cancel the request
String tag_string_req = "req_login";
progressDialog.setMessage("Logging in....");
progressDialog.show();
StringRequest strReq = new StringRequest(Request.Method.POST,
Utils.LOGIN_URL, new Response.Listener<String>() {
@Override
public void onResponse(String response) {
Log.d(TAG, "Login Response: " + response.toString());
try {
JSONObject jObj = new JSONObject(response);
boolean error = jObj.getBoolean("error");
//check for error node in json
if (!error) {
//now store the user in SQLite
JSONObject user = jObj.getJSONObject("user");
String uName = user.getString("username");
String email = user.getString("email");
//Inserting row in users table
userInfo.setEmail(email);
userInfo.setUsername(uName);
session.setLoggedin(true);
startActivity(new Intent(Login.this, MainActivity.class));
finish();
} else {
//error in login, get the error message
String errorMsg = jObj.getString("error_msg");
toast(errorMsg);
}
} catch (JSONException e) {
//json error
e.printStackTrace();
toast("Json error: " + e.getMessage());
}
}
}, new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
Log.e(TAG, "Login Error: " + error.getMessage());
toast("Unknown Error occured");
progressDialog.hide();
}
}) {
@Override
protected Map<String, String> getParams() {
//Posting parameters to login url
Map<String, String> params = new HashMap<>();
params.put("email", email);
params.put("password", password);
return params;
}
这是我收到错误的地方:
//Adding request to request queue
AndroidLoginController.getInstance().addToRequestQueue(strReq, tag_string_req);
}
答案 0 :(得分:1)
您在Response.Listener的结束大括号('}')之后缺少右括号。 (所以,最后应该至少有两个结束的花括号。)