Question

我在使用mixin进行媒体查询断点时遇到问题。我已经包含了variables.scss和_breakpoints.scss，但每当我尝试调用查询时它都会给我一个错误：

name <- c("Pablo", "Christina", "Steve", "Diego", "Ali", "Brit", "Ruth", "Mia", "David", "Dylan")
year <- seq(2000, 2009, 1)
v1 <- sample(1:10, 10, replace=T)
v2 <- sample(1:10, 10, replace=T)
df <- data.frame(name, year, v1, v2, stringsAsFactors=FALSE)
print(df)
rows = nrow(df)
n <- rows * (rows - 1) / 2
ndf <- data.frame(
    name1=character(n),year1=numeric(n), v1_1=numeric(n),v2_1=numeric(n),
    name2=character(n),year2=numeric(n), v1_2=numeric(n),v2_2=numeric(n),
    stringsAsFactors=FALSE
)
k <- 1
for (i in 1:(rows-1))
{
    for (j in (i+1):rows)
    {
        ndf[k,] <- c(df[i,], df[j,])
        k <- k + 1
    }
}
print(ndf)

#        name year v1 v2
#1      Pablo 2000  4  9
#2  Christina 2001  2  1
#3      Steve 2002  2  9
#4      Diego 2003  5  5
#5        Ali 2004 10  4
#6       Brit 2005  5  2
#7       Ruth 2006  7 10
#8        Mia 2007  6  7
#9      David 2008  4 10
#10     Dylan 2009  7  3

#       name1 year1 v1_1 v2_1     name2 year2 v1_2 v2_2
#1      Pablo  2000    4    9 Christina  2001    2    1
#2      Pablo  2000    4    9     Steve  2002    2    9
#3      Pablo  2000    4    9     Diego  2003    5    5
#4      Pablo  2000    4    9       Ali  2004   10    4
#5      Pablo  2000    4    9      Brit  2005    5    2
#6      Pablo  2000    4    9      Ruth  2006    7   10
#7      Pablo  2000    4    9       Mia  2007    6    7
#8      Pablo  2000    4    9     David  2008    4   10
#9      Pablo  2000    4    9     Dylan  2009    7    3
#10 Christina  2001    2    1     Steve  2002    2    9
#...

当我尝试编译时它会出现这个错误：

buscadorPorLapso

我该怎么写这个查询？

Answer 1

我有一个错字，说明@media，而不是@include。它现在有效。

bootstrap4媒体查询mixin无法正常工作

1 个答案: